If abc is triangular ABC trilateral, reduce the absolute value of square-(c-b-a) of (b-a-c) under the square-root sign of (a+b-c) If abc is a triangular ABC trilateral, reduce the absolute value of the square-(c-b-a) b-a-c) under (a+b-c)

If abc is triangular ABC trilateral, reduce the absolute value of square-(c-b-a) of (b-a-c) under the square-root sign of (a+b-c) If abc is a triangular ABC trilateral, reduce the absolute value of the square-(c-b-a) b-a-c) under (a+b-c)

Triangular relationship within triangle, a+b > c, a+c > b, a+b-c >0, a+c-b >0
So √(a+b-c)^2-√(b-a-c)^2-|c-b-a|
=A+b-c-(a+c-b)-(a+b-c)
=B-a-c

In a triangle ABC, a, b, c are the three sides of the triangle, square-2 of the simplified root number (a-b+c) multiplied by the absolute value of (c-a-b As shown in the figure, In a triangle ABC, a, b, c are the three sides of the triangle, square-two of the simplified root number (a-b+c) multiplied by the absolute value of (c-a-b As shown in the figure,

In a triangle, the sum of the two sides is greater than the third side, and the difference between the two sides is less than the third side, so a-b+c >0, c-a-b