If the absolute value of a-5 is opposite to the square of (b+1), then the third power of a + the 25th power of b

A-5|is opposite to (b+1)^2,
Then: a-5=0 a=5
B+1=0 b=-1

Given that the absolute value of 2a minus b and the square of (b minus 1) are mutually opposite find the cube of a plus b Given that the absolute value of 2a minus b is opposite to the square of (b minus 1), find the cube of a plus b

"If the absolute value of 2a minus b and the square of b minus 1 are mutually opposite, then there must be:2a-b=0b-1=0 solution: a=1/2; b=1(a+b)3=(1+1/2)3=(3/2)3=27/8

"If the absolute value of 2a minus b and the square of b minus 1 are mutually opposite, there must be:2a-b=0b-1=0 solution: a=1/2; b=1(a+b)3=(1+1/2)3=(3/2)3=27/8

RELATED INFORMATIONS

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