Given that the absolute value of the difference of 2a-b is opposite to the square of b-1, find the value of the cube of a+b

Given that the absolute value of the difference of 2a-b is opposite to the square of b-1, find the value of the cube of a+b

The opposite number adds up to 0
|2A-b (b-1)2=0
The absolute value and the square are greater than or equal to 0, and the sum is equal to 0. If one is greater than 0, the other is less than 0.
So both equal 0.
So 2a-b=0, b-1=0
B=1
A = b/2=1/2
So a+b3=1/2+1 3=3/2

The opposite number adds up to 0
|2A-b (b-1)2=0
The absolute value and the square are greater than or equal to 0, and the sum is equal to 0. If one is greater than 0, the other is less than 0.
So both equals zero.
So 2a-b=0, b-1=0
B=1
A = b/2=1/2
So a+b3=1/2+1 3=3/2

For example, if (a+1) square and absolute value of b+2 are mutually opposite, find the third power of a to the power of 2009+ab-b? For example, if (a+1) square and b+2 absolute value are mutually opposite numbers, find the third power of a to the 2009 power +ab-b?

Because a+1)^2=0,|b+2|=0a=-1, b=-2a^2009+ab-b^3=(-1)^2009+(-1)*(-2)-(-2)^3=-1+2+8=9, because the square of (a+1)≥0 and the absolute value of (b+2)≥0 are opposite to the absolute value of (b+2).

Because a+1)^2=0,|b+2|=0a=-1, b=-2a^2009+ab-b^3=(-1)^2009+(-1)*(-2)-(-2)^3=-1+2+8=9, because the square of (a+1)≥0, the absolute value of b+2≥0(a+1) and the absolute value of b+2 are opposite to each other.