Given a, b is a rational number and −a 3−5 And 2 are opposite to each other, a and b are reciprocal, try to find 2a+3 4Ab.

-A
3-5 And 2 are opposite numbers, a and b are reciprocal numbers,
-A
3-5+2=0, Ab=1,
Solution: a=-9,
Then 2a+3
4Ab=2×(-9)+3
4×1=-18+3
4=-171
4.

Given a, b is a rational number and −a 3−5 And 2 are opposite to each other, a and b are reciprocal, try to find 2a+3 4Ab.

-A
3-5 And 2 are opposite numbers, a and b are reciprocal numbers,
-A
3-5+2=0, Ab=1,
Solution: a=-9,
Then 2a+3
4Ab=2×(-9)+3
4×1=-18+3
4=-171
4.

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