The result of determining absolute value a+b-c minus absolute value b-a-c by known triangle abc The result of finding the absolute value a+b-c minus the absolute value b-a-c for a known triangle abc

The result of determining absolute value a+b-c minus absolute value b-a-c by known triangle abc The result of finding the absolute value a+b-c minus the absolute value b-a-c for a known triangle abc

The sum of the two sides of the triangle is greater than the third side
So a+b > c
A+c > b
So a+b-c >0
B-a-c <0
So |a+b-c|=a+b-c
|B-a-c|=a+c-b
Original formula = a+b-c-(a+c-b)
=2B-2c

The three points A, B and C on the given number axis represent rational numbers a,1 and -1 respectively, then |a+1| represents ()

Distance between ACs