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三角形兩邊之和大於第三邊 所以a+b>c a+c>b 所以a+b-c>0 b-a-c<0 所以|a+b-c|=a+b-c |b-a-c|=a+c-b 原式=a+b-c-(a+c-b) =2b-2c
AC之間的距離
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