Using the square difference formula: how much is the 2nd power of 2007 minus 2008 times 2006?

Using the square difference formula: how much is the 2nd power of 2007 minus 2008 times 2006?

The second power of 2007 minus 2008 times 2006 equals =2007^2-(2007+1)(2007-1)=2007^2-2007^2+1=1

Calculate the power of 3 for 2006-5*3 for 2005+6*3 for 2004+2006 Calculate 3's 2006 power-5*3's 2005 power+6*3's 2004 power+2006

3^2006-5*3^2005+6*3^2004+2006
=3^(2004)(3^2-5*3+6)+2006
=3^(2004)*0+2006
=0+2006
=2006