Given |a-1(b+2)2=0, find the value of (a+b)2009+a2010.

A-1(b+2)2=0,
A-1=0, b+2=0,
Solve a=1, b=-2,
(A+b)2009+a2010=(1-2)2009+12010=-1+1=0.

If A =25, B =-3, try to determine the end of A's 2012 power + B's 2011 power

How many times the end is 5, the end is 5.
And the number at the end of -3 is 3,9,7,1 cycle 2011 divided by 4, and the rest is 3, so it's 7.
Answer 5+7= End of 12
Yes 2

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