What is the unit vector a0 in the same direction as vector a=(1,2

What is the unit vector a0 in the same direction as vector a=(1,2

A0=(1/Root 5,2/Root 5)

A0=(1/root #5,2/root #5)

If vector a=(1,2,0,1) unitized unit vector a0=___

|A|=sqrt6, so a0=(sqrt6/6, sqrt6/3,0, sqrt6/6).
Sqrt represents square root

Given the vector a-(3,4), then its unit vector a0=

The unit vector a0 of vector a =(3/5,4/5)

Vector a=(3,4), then its basic unit vector a0 is

AO is (4,5)

Find the coordinates of the unit vector parallel to a =(5,12)

5^2+12^2=13^2
A = Coordinates of (5,12) parallel unit vectors =(5/13,12/13)

Abc is the unit vector and ab=0, then the minimum value of |a+b-c| is

|A||=|b||=|c||=1, a·b=0, then:|a+b-c|^2=(a+b-c)·(a+b-c)=|a+b|^2 c|^2-2c·(a+b)=|a|^2 b|^2 c|^2-2c·(a+b)=3-2|c a+b|*cos=3-2 sqrt (2)*cos When c and a+b are in the same direction,|a+b-c| takes the minimum value: sqrt (2)-1