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Given three points A (1,1) B (-1,0) C (0,1), find another point D (x, y) so that vector AB = vector cD
It is easy to know,
Vector AB=(-2,-1)
Vector CD=(x, y-1)
∴(-2,-1)=(X, y-1)
-2=X,-1=y-1.
X=-2, y=0
D (-2,0)
P={(-1,1)+m (1,2) m∈R}, Q={=(1,-2)+n (2,3) n∈R} are two sets of vectors, then P∩Q is equal to P={α(-1,1)+m (1,2) m∈R}, Q={β=(1,-2)+n (2,3) n∈R} are two vector sets, then P∩Q is equal to
(-1+M,1+2m)=(1+2n,-2+3n).-1+m=-+2n,1+2m=-2+3n.
M=-12, n=-7, P∩Q={(-13,-23)}
A vector is known to be non-zero, b vector is (3,4), a vector is perpendicular to b vector Find the unit term of a vector A vector is known to be non-zero, b vector is (3,4), a vector is perpendicular to b vector. Find the unit term of a vector Vector a is known to be non-zero, vector b is (3,4), vector a is perpendicular to vector b. Find the unit term of vector a
Vertical is a point multiplication b equals 0. Point multiplication is a point, and the difference multiplication "×" is parallel. a*b=0 Let a (x, y)=>3x+4y=0=> y=-3/4x, then t (1,-3/4) can be obtained. But it needs to be unitized to get a.
Vertical is a point times b is equal to 0. Point times is a point, and the difference multiplication "×" is parallel. a*b=0 Let a (x, y)=>3x+4y=0=> y=3/4x, then t (1,-3/4) can be obtained. But it needs to be unitized to get a.
Given the vector a=(1,1), b=(2,-1), if (a b)·b=0, then how many? Given the vector a=(1,1), b=(2,-1), if (a b)·b=0, then the real number λ is?
(A b)·b=2(1+2λ)-(1-λ)=0
λ=-1/4
Given A (3,5,7), B (-2,4,3), find the vector AB, the vector BA, the midpoint coordinates of the segment AB and the length of the segment AB
Vector AB=B-A=(-5,-1,10)
Vector BA=-vector AB=(5,1,-10)
Length of line segment AB=|vector AB|=√[(-5)2+(-1)2+(10)2]=√126=3√14
Midpoint coordinate of line segment AB =(A+B)/2=(1/2,9/2,-2)
Let A (-2,2) B (-1,4) C (4) C (4,-5) and vector A B =(1/2) vector CD, and find the coordinates of point D.
Let D (x, y)
Vector AB=(1,2) Vector CD=(x-4, y+5)
Because vector AB =(1/2) vector CD
So 1=1/2(x-4)2=1/2(y+5)
X=6 y=-1
Let D (x, y)
Vector AB=(1,2) Vector CD=(x-4, y+5)
Because vector AB=(1/2) vector CD
So 1=1/2(x-4)2=1/2(y+5)
X=6 y=-1
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