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Given vector a=(-2,3) b=(3,1) c=(10,4) try ab means C is urgent
Let c=xa+yb
Then -2x+3y=10
3X+y=-4
Solution x=-2, y=2
So c=-2a+2b
Given vector a=(10,-4).b=(3,1) c=(-2,3) try b, a, indicate a
Should be:
Trial b, c, design
A=x1b+x2c
10=3X1-2x2 1
-4= X1+3x2 2
①-②×3, Get
22=-11X2
X2=-2
Substitute 2, get
-4= X1-6
X 1=2
So
A=2b-2c
Should be:
Trial b, c, design
A=x1b+x2c
10=3X1-2x2 1
-4= X1+3x2 2
①-②×3, Get
22=-11X2
X2=-2
Substitute 2 to obtain
-4= X1-6
X1=2
So
A=2b-2c
Given vector a=(0,1), vector b=(3,4), then the projection of vector a in vector b equals
The projection of vector a in vector b equals |a|cos=|a (a*b)|/|a b|=|a*b|/|b|=4/5
It is known that the direction of vector b is the same as that of vector a=(-3,4), and the absolute straightness of vector b=15, then b=? The direction of vector b is known to be the same as the direction of vector a=(-3,4), and the absolute straightness of vector b=15, then b=?
B=(x, y)
Know
-3/X=4/y
X2+ y2=15 2
X <0
Y >0
Jiede
X=-9, y=12
Vector b=(-9,12)
What is the number of orthophones of vector a=(5,2) in vector b=(-2,1)? How to understand the number of positive projections, the difference between projection and projection?
Hello, orthographic refers to a point to a straight line to make a vertical line, vertical foot projective
The orthographic projection of vector a in direction b is a vector, i.e. the vector from the origin to the projection point
The projection in the vector refers to the quantity, i.e. the projection of a in the b direction:|a|*cos
A=(5,2), b=(-2,1), then:|a|=sqrt (29),|b|=sqrt (5), and: a·b=-8
Therefore: cos=a·b/(|a b|)=-8/sqrt (29*5)
So a projective:|a|*cos (π-)*(-b)/|b|=sqrt (29)*(8/sqrt (29*5))*(2,-1)/sqrt (5)
=(16/5,-8/5)
A Projection in direction b:|a|*cos=sqrt (29)*(-8/sqrt (29*5))=-8/sqrt (5)=-8sqrt (5)/5
Given that the absolute value of vector a is equal to 4 and the number of orthophones of vector b in the direction of vector a is -6, then the point of vector a multiplied by vector b is equal to?
-24
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