Given two points A [4,0,5] and B [7,1,3], find the unit vector parallel to vector AB.
0
Given A (3,1), B (-5,7), the unit vector in the same direction as vector AB is the unit vector in the opposite direction to vector AB.
0
Given the vector (7,8) B vector (3,5), then the unit vector coordinate in vector AB direction is?
0
Given that the vector ab satisfies the norm of vector a is 1, the norm of vector b is 2, and the norm 2a+b=2, then the projection of vector b in the direction of vector a () A.-1/2 B-1 C1/2 D1
Modulus of 2a+b =2
Modulus of 2a =2
Module of b =2
120° Between a and b
B The projection in the rea direction is -2* cos60°=-1
Option B
Modulus of 2a+b=2
Module of 2a =2
Module of b =2
120° Between a and b
B The projection in the rea direction is -2* cos60°=-1
Option B
The point B (2,-1) is known, and the origin is O The ratio of AB is -3, and B=(1,3), find B In The projection on AB. The point B (2,-1) is known, and the origin is 0 min. The ratio of AB is -3, and B=(1,3), find B In The projection on AB.
Let A (x, y),
AO
OB =-3
∴
AO=-3
OB i.e.(-x,-y)=-3(2,-1)
X=6, y=-3 i.e. A (6,-3)
∴
AB=(-4,2),
∴|
AB |=
20∴
B In
.
The projection on AB is
B
AB
|
AB |=
5
5
Given a vector=3, b=5, and a·b=12, the projection of vector a on vector b is A.12/5 B.3 C.4 D.5
Projection of a on b=|a|cos=ab/|b|=12/5
Select [A]