Given vector a=(2,1), ab=10.,{ a+b }=5 times root 2. Then b=? 5+2*10+B^2b^2 Given the vector a=(2,1), ab=10.,{ a+b }= times root 2. Then b=? 5+2*10+B^2+b^2 Given the vector a=(2,1), ab=10.,{ a+b }=5 times root 2. Then b=? How do I get 5+2*10+b^2

Given vector a=(2,1), ab=10.,{ a+b }=5 times root 2. Then b=? 5+2*10+B^2b^2 Given the vector a=(2,1), ab=10.,{ a+b }= times root 2. Then b=? 5+2*10+B^2+b^2 Given the vector a=(2,1), ab=10.,{ a+b }=5 times root 2. Then b=? How do I get 5+2*10+b^2

|A+b|^2=a^2+2ab+b^2
50=5+2*10+B^2
B^2=25
|B |=5

Vector a=(1, m) b=(-2,4) and ab=-10, then m=

M=-2
1*4=-2*M
That's what I' m supposed to do. I haven't done this in a long time.

Vector a (2.1) ab=10 a + b's touch =2 times root 5 for b's touch Number of Chinese Characters in 2009

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Solution of Plane Normal Vector in Solid Geometry Let m (x, y, z) be the normal vector of a plane. Let m*a=0m*b=0.(a, b∈aαa∩b=c) be the posterior solution equation. (Detailed description) Solution of Plane Normal Vector in Solid Geometry Let m (x, y, z) be the normal vector of a plane. Let m*a=0m*b=0.(a, b∈aαa∩b=c) be the posterior solution equation. Then how to proceed? (Detailed description) Solution of Plane Normal Vector in Solid Geometry Let m (x, y, z) be the normal vector of a plane. Let m*a=0m*b=0.(a, b∈αa∩b=c) be the posterior solution equation. Then how to proceed? (Detailed description)

The result has a common unknown in the three components of the normal vector.
For example, if the result is (x,2x,4x), then the normal vector is (1,2,4).
In fact, if the plane is not parallel to the x-axis, the vector can be (1, x, y), and there are only two unknowns.

The result has a common unknown in the three components of the normal vector, which can be set to any nonzero real number.
For example, if the result is (x,2x,4x), then the normal vector is (1,2,4).
In fact, if the plane is not parallel to the x-axis, the vector can be (1, x, y), and there are only two unknowns.

Space vector distance What is the formula for a space vector to find the distance between faces?

Take any two points A (x1, y1, z1), B (x2, y2, z2)
Find vector AB
Since the planes are parallel, only one normal vector N (x, y, z) is required
Distance D=[ AB*N ]/|n|

How to Find the Distance from Point to Space Vector For example, the distance between point p (a, b, c) and vector A (d, e, f) How to find the distance from point to space vector For example, the distance between point p (a, b, c) and vector A (d, e, f)

The vertical line isd, ke, kf) be pk vector (kd-a, ke-b, kf-c) and then find k according to the perpendicularity of the two vectors.

The vertical line isd, ke, kf) be pk vector be (kd-a, ke-b, kf-c) and then find k according to the perpendicularity of the two vectors and then find the length of pk.