A right triangle has a right angle side of 6m and an oblique side of 12m long. If the height of the hypotenuse is known to be 2m, the length of the other side of the triangle is A right triangle has a right angle side of 6 meters long and an oblique side of 12 meters long. If the height corresponding to the oblique side is known to be 2 meters, what is the length of the other right angle side of the triangle?

A right triangle has a right angle side of 6m and an oblique side of 12m long. If the height of the hypotenuse is known to be 2m, the length of the other side of the triangle is A right triangle has a right angle side of 6 meters long and an oblique side of 12 meters long. If the height corresponding to the oblique side is known to be 2 meters, what is the length of the other right angle side of the triangle?

Solution: directly use Pythagorean theorem: let another right angle side be x, then x ^ 2 + 6 ^ 2 = 12 ^ 2. X ^ 2 = 12 ^ 2-6 ^ 2 = 144-36 = 108, x = ± √ 108 = ± 6 √ 3 (m) x = 6 √ 3

The height of a right triangle is 2m, and the oblique side is 5m to find the side length

5 ^ 2-2 ^ 2 = 21, the square root is 21

A right triangle steel plate is drawn on the map with a scale of 1:200. The length of the two right angle sides is 5.4 cm, and their ratio is 5:4. What is the actual area of this steel plate?

5.4÷1
200 = 1080 (CM),
5 + 4 = 9 (CM),
1080×5
9 = 600 (CM) = 6 (m),
1080×4
9 = 480 (CM) = 4.8 (m),
Area: 6 × 4.8 △ 2 = 14.4 (square meters);
A: the actual area of this steel plate is 14.4 square meters

Draw a right triangle steel plate with a scale of 1:200. The length of the two right angle sides is 5.4cm, and the ratio of their length is 5:4 How many square meters is the real area

Length: 5.4 × 5 / (5 + 4) = 3 width: 5.4-3 = 2.4
Actual length: 3 × 200 = 600cm = 6m actual width: 2.4 × 200 = 480cm = 4.8m
Actual area: 6 × 4.8 = 28.8 square meters

Know how to find the angle of the length of three sides of a right triangle

Use trigonometric function to find
The trigonometric function has sin ∠ a = opposite side than up slope
Cos ∠ a = adjacent edge to upper slope
Tan ∠ a = opposite side to upper adjacent side
Find the values of these trigonometric functions, and use the inverse trigonometric functions to calculate the values of these trigonometric functions
Special values directly corresponding to

Knowing the length of two sides of a right triangle how to find the other side

The two open sides of the sum of squares

A right triangle, two right sides are 6cm and 10cm respectively. After rotating along the oblique side for one cycle, we can get a rotating body. What's the volume of the rotator?

As shown in the figure:
AB=6，BC=10，AC=2
34，OB=15
Thirty-four
17，
V=1
3×π×OB2×AC，
=1
3×3.14×15
Thirty-four
17×15
Thirty-four
17×2
34，
=942
Thirty-four
17 (cubic centimeter);
A: the volume of 942
Thirty-four
17 cubic centimeters

A right triangle, two right sides are 6cm and 10cm respectively. After rotating along the oblique side for one cycle, we can get a rotating body. What's the volume of the rotator?

As shown in the figure:
AB=6，BC=10，AC=2
34，OB=15
Thirty-four
17，
V=1
3×π×OB2×AC，
=1
3×3.14×15
Thirty-four
17×15
Thirty-four
17×2
34，
=942
Thirty-four
17 (cubic centimeter);
A: the volume of 942
Thirty-four
17 cubic centimeters

A right triangle, two right sides are 6cm and 10cm respectively. After rotating along the oblique side for one cycle, we can get a rotating body. What's the volume of the rotator?

As shown in the figure:
AB=6，BC=10，AC=2
34，OB=15
Thirty-four
17，
V=1
3×π×OB2×AC，
=1
3×3.14×15
Thirty-four
17×15
Thirty-four
17×2
34，
=942
Thirty-four
17 (cubic centimeter);
A: the volume of 942
Thirty-four
17 cubic centimeters

A right triangle, the two right sides are 3cm and 4cm respectively, and the oblique side is 5cm long. After rotating around the hypotenuse, we can get a revolving body. What is the volume of the revolving body?

Seen from the height on the hypotenuse, the height on the hypotenuse divides the body of revolution into two cones
The bottom radius of the cone is 3 * 4 / 5 = 12 / 5 of the height on the bevel
If the height of the two cones is H1, H2, then H1 + H2 = bevel = 5
Then the volume of the body of revolution is the sum of the volumes of the two cones
=1/3π*r²h1+1/3π*r²h2
=1/3π*r²（h1+h2）
=1/3π*（12/5）²*5
=48/5*π
=30.144