C:\Documents and Settings\Administrator\My Documents\My Pictures ABC is an isosceles right triangle, BC = AC = 8cm

C:\Documents and Settings\Administrator\My Documents\My Pictures ABC is an isosceles right triangle, BC = AC = 8cm

Picture?

As shown in the figure, ABC is an isosceles right triangle with two small squares inside

16×16-（16÷2）×（16÷2）÷2×2，
=256-64，
=192 (square centimeter);
A: the shadow area is 192 square centimeters

As shown in the figure, △ ABC and △ def are isosceles right triangles, ab = 8 cm, de = 6 cm. Calculate the shadow area

According to the analysis, it can be seen that:
FE=DE=AE，BE=AB-AE，GB=DB=DE-BE，
Then EF = 6 cm,
Be = ab-ae = ab-de = 8-6 = 2cm,
GB = DB = de-be = 6-2 = 4cm,
So the area of the shadow part is: (4 + 6) × 2 △ 2 = 10 (square centimeter);
A: the shadow area is 10 square centimeters

In the figure, △ ABC and △ ade are isosceles right triangles. BC is 8 cm long and De is 4 cm long

4 △ 2 = 2 (CM), 8 △ 2 = 4 (CM),
8×4÷2-4×2÷2，
=16-4，
=12 (square centimeter),
A: the shadow area is 12 square centimeters

As shown in the figure, both the triangle ABC and the triangle def are isosceles right triangles, ab = 8cm, de = 9cm, calculate the shadow area

I don't know whether my drawing is right or not. According to my drawing, it is actually a trapezoid. Because they are isosceles right triangle, subtracting the overlapping length is the length of the upper and lower bottom, and the height is the overlap width
Therefore, let large RT △ side length = a small RT △ side length = B overlap width = H
Then s shadow = (top + bottom) height / 2 = [(A-H) + (B-H)] H / 2 (general formula)
S shadow = [(9-2) + (8-2)] 2 / 2 = 7 + 6 = 13cm

In the figure, △ ABC and △ ade are isosceles right triangles. BC is 8 cm long and De is 4 cm long

4 △ 2 = 2 (CM), 8 △ 2 = 4 (CM),
8×4÷2-4×2÷2，
=16-4，
=12 (square centimeter),
A: the shadow area is 12 square centimeters

In the figure, △ ABC and △ ade are isosceles right triangles. BC is 8 cm long and De is 4 cm long

4 △ 2 = 2 (CM), 8 △ 2 = 4 (CM),
8×4÷2-4×2÷2，
=16-4，
=12 (square centimeter),
A: the shadow area is 12 square centimeters

As shown in the figure, after translating the right triangle ABC along the CB direction by the distance be, we can get the right triangle def, known as Ag = 2, be = 4 How to calculate the area of dgbe?

G point is the intersection of AB and DF!
Because △ DEF is derived from △ ABC translation
∴AB=DE=6 ,∴BG=6-2=4
Because of the equal distance between B and C
∴CF=BE=4
The common area of △ def and △ ABC is the area of △ GFB
The shadow area = the area of right angle trapezoid gbed = 4 (4 + 6) / 2 = 20

As shown in the figure, translate the right triangle ABC along the AB direction to get the right triangle def, known as be = 5, EF = 8, CG = 3. Calculate the area of shadow part in the graph As shown in the figure Speed Just tonight Offer a reward! 。

The area of the shadow is actually equal to the area of befg

The hypotenuse of an isosceles right triangle is 8 cm long and its area is______ .

Square area: 8 × 8 = 64 (cm2),
Area of triangle: 64 △ 4 = 16 (cm2),
A: the area of the triangle is 16 square centimeters
So the answer is: 16 square centimeter