The difference between the two right angles of a triangle is 5cm and the area is 7cm 2

The difference between the two right angles of a triangle is 5cm and the area is 7cm 2

Let the shorter right angle side be xcm, and the longer one is (x + 5) cm,
One
2x•（x+5）=7，
The result is: x2 + 5x-14 = 0,
∴（x+7）（x-2）=0，
Ψ x = 2 or x = - 7 (omitted)
5+2=7cm，
22+72=
53cm．
The length of the hypotenuse is
53cm．

The difference between the two right angles of a triangle is 5cm and the area is 7cm 2

Let the shorter right angle side be xcm, and the longer one is (x + 5) cm,
One
2x•（x+5）=7，
The result is: x2 + 5x-14 = 0,
∴（x+7）（x-2）=0，
Ψ x = 2 or x = - 7 (omitted)
5+2=7cm，
22+72=
53cm．
The length of the hypotenuse is
53cm．

If one of the right angles of a right triangle is twice that of the other, and the length of the hypotenuse is 5, then the area of the right triangle is______ .

Let the two right sides of the right triangle be x and 2x respectively, and the length of the oblique side is 5,
Then x2 + (2x) 2 = 52,
The solution is X=
5, so the right side of the right triangle is
5，2
5，
The area of this right triangle is s = 1
2 x
5×2
5=5，
So the answer is 5

The difference between the two right angles of a triangle is 5cm and the area is 7cm 2

Let the shorter right angle side be xcm, and the longer one is (x + 5) cm,
One
2x•（x+5）=7，
The result is: x2 + 5x-14 = 0,
∴（x+7）（x-2）=0，
Ψ x = 2 or x = - 7 (omitted)
5+2=7cm，
22+72=
53cm．
The length of the hypotenuse is
53cm．

The difference between the two right angles of a triangle is 5cm and the area is 7cm 2

Let the shorter right angle side be xcm, and the longer one is (x + 5) cm,
One
2x•（x+5）=7，
The result is: x2 + 5x-14 = 0,
∴（x+7）（x-2）=0，
Ψ x = 2 or x = - 7 (omitted)
5+2=7cm，
22+72=
53cm．
The length of the hypotenuse is
53cm．

The difference between the two right angles of a triangle is 5cm and the area is 7cm 2

Let the shorter right angle side be xcm, and the longer one is (x + 5) cm,
One
2x•（x+5）=7，
The result is: x2 + 5x-14 = 0,
∴（x+7）（x-2）=0，
Ψ x = 2 or x = - 7 (omitted)
5+2=7cm，
22+72=
53cm．
The length of the hypotenuse is
53cm．

The difference between the two right angles of a triangle is 5cm and the area is 7cm 2

Let the shorter right angle side be xcm, and the longer one is (x + 5) cm,
One
2x•（x+5）=7，
The result is: x2 + 5x-14 = 0,
∴（x+7）（x-2）=0，
Ψ x = 2 or x = - 7 (omitted)
5+2=7cm，
22+72=
53cm．
The length of the hypotenuse is
53cm．

Please use elementary school knowledge to solve an isosceles right triangle's hypotenuse length of 8 cm, what's its area

Because it is an isosceles right triangle, the height is half of the hypotenuse, that is 4cm. The area is s = 8 × 4 △ 2 = 16 square centimeter

If the base of an isosceles right triangle is 8 cm, what is its area?

8×（8÷2）÷2，
=8×4÷2，
=16 (square centimeter);
A: the area of a right angle triangle is 16 centimeters

The area of a right triangle is 150 square meters. The ratio of its two right angles is 3:1. Find the length of these two right angles

The ratio of its two right angles is 3:1, and the two right angles are 3x, X respectively
So s = 3x * x / 2 = 150, x = 10 meters
So its two right angles are 30 meters and 10 meters