If the two sides of a right triangle are 12 and 5 respectively, the area of an isosceles triangle with its third side as the right angle side is 0______ .

There are two cases
① When 12 is a right angle side,
The third side is
122+52=13，
The area of isosceles triangle with its third side as right angle side is 1
2×132=84.5；
② When 12 is bevel edge,
The third side is
122−52=
119，
The area of isosceles triangle with its third side as right angle side is 1
2×（
119）2=59.5．
So the answer is 84.5 or 59.5

If an acute angle of a right triangle is 30 degrees, what is the degree of the acute angle formed by the bisector and the hypotenuse of the right angle?

180-（90-30）-90/2=75
So the degree of the acute angle formed by the bisector and the hypotenuse of a right angle is 75 degrees

Given that the circumference of a right triangle with 30 degree acute angle is 1, what is its area

Because this is a right triangle with 30 degree acute angle, the ratio of three sides can be obtained according to the formula: 1: √ 2:2, then its area can be calculated:
{1÷（3+√2）*√2]* [1÷（3+√2）]}/2
=√ 2 / 22 + 12 √ 2 (i.e. 22 + 12 √ 2)
A: its area is √ 2 / 22 + 12 √ 2
I hope you can be satisfied with my answer!

If the difference between the two acute angles of a right triangle is 10 °, what are the degrees of these two acute angles?

The reason for 50 ° and 40 ° is very simple. One of the right triangles is 90 ° so the other two are 90 ° and X + y = 90 X-Y = 90. The solution is x = 50, y = 40

In a right triangle, the difference between two acute angles is 50 degrees

Let one of the angles be x and the other y
x+y=90
x-y=50
X = 70, y = 20

In a right triangle, if the difference between two acute angles is 40 degrees, then the degrees of these two acute angles are______ .

Let the degrees of these two acute angles be x, y, respectively,
According to the meaning of the title,
x−y＝40
x+y＝90 ，
The solution
x＝65
y＝25 ．
So the answer is: 65 ° and 25 ° respectively

If the acute angle a of a right triangle is 20 degrees larger than that of B, what is the base of the acute angle a?

A + B = 90 ° A-B = 20 ° leads to a = 55 ° B = 35 °

In a right triangle, if the degree ratio of an acute angle to a right angle is 3:5, then the degree ratio of two acute angles is () A. 2:5 B. 5:3 C. 3:2

According to the degree ratio of an acute angle to a right angle is 3:5,
Think of an acute angle as three parts,
The other acute angle is: 5-3 = 2,
The ratio of two acute angles is: 3:2;
Therefore, C

How to find both sides of a right triangle when the length of its right angle side is 6 and the degree of acute angle is 6.93 In a hurry Height = 6, minimum acute angle = 6.93. .......

Let △ ABC, ∠ C = 90 °,
∠B=6.93°,AC=6,
(1) From sin ∠ B = 6 / AB,
∴AB=6/sin∠B
AB=6/0.12=50,
（2）BC²=AB²-AC²,
∴BC²=50²-6²=2464,
∴BC=49.6.

One acute angle of a right triangle is 36.5 degrees. What is the other acute angle Teach me Using equation solution

Oh my God! 90-36.5 = 53.5 degrees

If the two sides of a right triangle are 12 and 5 respectively, the area of an isosceles triangle with its third side as the right angle side is 0______ .