The ratio of one right angle side to the hypotenuse of a right triangle is 12:13, and the length of the other right angle side is 5cm. What is the area of this right triangle?

The ratio of one right angle side to the hypotenuse of a right triangle is 12:13, and the length of the other right angle side is 5cm. What is the area of this right triangle?

 

Given that the degrees of the three angles of a right triangle are 90 degrees, 33 degrees 41 ', 56 degrees 59' and a right angle side length of 6 mm, find another right angle

Two possibilities: if the right angle side is a long right angle side, then let the other side be n, which is: Tan33 ° 41 '= n / 6, ﹥ n = 6 * Tan33 ° 41' ≈ 4mm; if this right angle side is a short right angle side, then let the other side be m, which has: tan56 ° 59 '= m / 6, ﹥ M = 6 * tan56 ° 59' ≈ 9.24mm;

Right triangle bottom 5.5 straight side 25.545 a 90 degree right angle what is the formula for calculating a 12 degree angle

tan-1(5.5/25.545)≈12.15°

For a right triangle, the degrees of the three angles are 15, 75 and 90 degrees respectively, and the shortest right angle side is 960. Find the other two sides

The other right angle side is 960 * tan75 = 3583
The bevel is 960 / sin15 = 3709

A right triangle, angle c = 90 degrees, hypotenuse C = 10, two right angles a + B = 14?

Since the angle c = 90 degrees, there is a Pythagorean theorem to obtain A2 + B2 = C2, that is, A2 + B2 = 100, which is equivalent to (a + b) 2-2ab = 100, and a + B = 14, so AB = 48 and area s = AB / 2 = 24

Given a right triangle, the length of a shorter right angle side is 30, and the three angles are 90 °, 57 ° and 33 ° respectively. Find out the length of the other two sides

The hypotenuse is 55.1, and the right angle is 46.3
Refer to sine cosine table for details

Given that the angle of a right triangle is 90, 70, 20 and the length of the longer right angle side is 30, find the length of the other two sides? How to calculate the formula

The 30 sincox / s x = 70 edges

The ratio of the lengths of the two right sides of a right triangle is 3:2, and the length of the hypotenuse is √ 520 Come on, it's better to add points in five minutes

Let the two sides of the right triangle be 2x and 3x, respectively
With the Pythagorean theorem, it is obtained that: (2x) 2 + (3x) 2 = (√ 520) 2
13x²=520
x²=40
X = 2 √ 10 x = - 2 √ 10 (omitted)
2x=2×2√10=4√10.
3x=3×2√10=6√10.

It is known that the right angle to which the 30 ° angle in a right triangle is equal to half of the hypotenuse, ∠ C = 90 ° and ∠ B = 15 ° The vertical bisector of AB intersects BC at D and ab at e, BD = 10. Find the length of AC

It is easy to know RT ∽ ABC ﹤ RT △ DBE, so Ed / BD = AC / AB = AC / (AE + EB), and e point is the midpoint of AB (vertical bisector), so the above formula = AC / 2be, that is, Ed / BD = AC / 2be
Ed = BD * sin15, be = BD * cos15, BD = 10, substituting into the above formula, the
BD * sin15 / BD = AC / 2 * BD * cos15, then AC = 2 * 10 * sin15 * cos15 = 10 * sin30 = 10 * 1 / 2 = 5

In a right triangle, the hypotenuse is equal to nine-thirds of the root sign 401, and the right angle sides are 4.5 and 90 respectively?

∵ hypotenuse = √ (square of one right angle edge + square of another)
   =√(90^2+4.5^2)=√(8100*4/4+81/4)=9*(√401) /2
The angle corresponding to the small side is 0 degrees
In theory, the three sides can not form a triangle, and the graph should be a straight line