Is there any way to calculate the value of special angle function? What degree is cos 82.8; Cos 42.3; Cos 0.725; Cos 0.9086?

Is there any way to calculate the value of special angle function? What degree is cos 82.8; Cos 42.3; Cos 0.725; Cos 0.9086?

The so-called special angle is the angle that can be related to 30,60,90. If it is the type of cosa = 0.725, we can calculate the degree of 15 ° and 45 ° which is usually the angle we often encounter when we do problems, or the common right triangle (side is 3,4,5 or 5,12,13, etc.)
You can use a calculator to calculate and remember when you have nothing to do
cos 82.8=0.1253(33233564304);cos42.3=0.7396(3109497861);(cos)-1 0.725=43.53°;(cos)-1 0.9086=24.6874°

Right triangle function problem In the right triangle ABC, ∠ C = 90 ° if AB = 4, BC = 2, radical 3, then a Cos - how much is cos Two There are the following options A. root 3 / 2 b. root 3 / 3 C. root 3 d. 2 - root 3 I calculated that cosa = 1 / 2, that is 1 / 4, but why not cosa is equal to 1 / 2

In the right triangle ABC, ab = 4, BC = 2 √ 3, the result is: a = 60 ° cosa = 1 / 2
Cosa / 2 = cos30 = √ 3 / 2 (√: root sign)

Are ortho functions and cosine functions only used on right triangles

In high school, the definition of trigonometric function is in a unit circle
There are also some formulas, such as the sine theorem: A / Sina = B / SINB = C / sinc = 2R in a triangle
Cosine theorem: A ^ 2 = B ^ 2 + C ^ 2-2bc * cosa
There are also some trigonometric transformations often used in evaluation and proof

What is the function of the opposite side of a right triangle to its adjacent side? If the opposite side is 10 mm and the adjacent side is 273 mm, what is the angle to 10 mm? If the opposite side is 10 and the hypotenuse is 273, what is the angle?

The opposite side is tan, which is the tangent function
If we take the angle, it's arctan (10 / 273)

For a right triangle with an angle of 60 degrees, the relation between its area y and its hypotenuse x is? As the title

The square of y = 0.5 ×√ 0.75 × x
√ stands for radical

For a right triangle of area 10, the center line of the hypotenuse is x, and the height of the hypotenuse is y For a right triangle of area 10, the center line of the hypotenuse is x and the height of the hypotenuse is y Find (1) the functional relationship between Y and X (2) write the value range of independent variable x (3) when x = 5, find the value of Y

The center line on the hypotenuse of a right triangle is equal to half of the hypotenuse
The center line of the hypotenuse is X
The slant side length is 2x
The height of the hypotenuse is y
∴S=1/2*(2X)*Y=XY=10
∴Y=10/X
The vertical distance from a point outside the line to the straight line is the shortest, ﹥ y ≤ X
Again: xy = 10
∴X^2≥10
ν x ≥ √ 10, that is, X ∈ (√ 10, + ∞)
When x = 5, y = 10 / 5 = 2

For a right triangle with an area of 10 and a 30 ° angle, the length of the shortest side is x, and the height of the hypotenuse is y. write the functional relationship between Y and X and the value range of X. thank you

The shortest side is x, the hypotenuse is 2x, and the other right angle side is root 3 X
Root 3 x * x = y * 2x = 20
Y = root 3 / 2 * x
Root 3 x * x = 20
X = 3.4 (approximately)

Given that the length of the hypotenuse of an isosceles right triangle is x and its area is y, then the functional relationship between Y and X is______ .

As shown in the figure:
∵AC=BC,AC⊥BC,S△ABC=y.AB=x,
∴AC2+BC2=x2,
∴2AC2=x2,
AC2=x2
2,
∵S△ABC=1
2AC•BC=1
2AC2=y,
∴y=1
2×x2
2=x2
4.
So the answer is: y = x2
4.

There is a right triangle with an angle of 60 ° and the functional relationship between its area s and the length of the hypotenuse x is______ .

∵ there is a right triangle with an angle of 60 degrees,
ν let ∠ a = 60 ° then ∠ B = 30 °,
∵ the slope length is X,
∴AC=1
2x,BC=
Three
2x,
The functional relationship between its area s and the length of the hypotenuse x is: S = 1
2×1
2x×
Three
2x=
Three
8x2.

In the RT triangle ABC, if the difference between the two right sides is 2cm, and the hypotenuse C = 10cm, then the height of the hypotenuse is?

Let a right angle side be X. then another right angle side is y (x > y)
x-y=√2
x^2+y^2=10
The solution is: x = 2 √ 2cm, y = √ 2cm
From the equal product formula, we can get the following results
xy=c*h
The solution is: H = 2 √ 10 / 5 (CM)
So the height on the bevel is 2 √ 10 / 5cm