In the right triangle ABC, given the right angle side a = root 96, hypotenuse C = root 150, calculate the circumference of the triangle ABC, 18 times 2

In the right triangle ABC, given the right angle side a = root 96, hypotenuse C = root 150, calculate the circumference of the triangle ABC, 18 times 2

In the right triangle ABC, given that the right angle side a = root 96, hypotenuse C = root 150, find the circumference of the triangle ABC, 18 times the root 2
The other right angle side = √ (150-96) = √ 54 = 3 √ 6;
Perimeter = 4 √ 6 + 3 √ 6 + 5 √ 6 = 12 √ 6;
18 times 2
=√（18×2）
=√36
=6；
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In the right triangle ABC, the difference between the two right sides is root 2, and the length of the hypotenuse is root 10. Find the height h on the hypotenuse

Double radical five

In the right triangle ABC, if the root of two right sides is 2, and the hypotenuse is 10, then the height of the hypotenuse is []

Suppose one side x, the other side x + radical 2
therefore
X ^ 2 + (x + radical 2) ^ 2 = 10
2X ^ 2 + 2 + 2x radical 2 = 10
X ^ 2 + radical 2X-4 = 0
X = radical 2
So on the other side, there are two root signs
According to the formula of triangle area
2 * (2 root number 2) = high * root number 10
So the height = 4 roots, 2 / 10 = 2 roots, 2 / 5

The length of the right triangle is 2.3 cm. The length of one side of the right angle is 2.6 cm

Two can be drawn at 4cm or 9cm

In a right triangle, knowing that an angle is 60 degrees and the long right angle side is 3.2, how to find the hypotenuse and the low side

The other angle is 30 degrees
Let the short right angle side be x, then the hypotenuse is 2x,
So x ^ 2 + 3.2 ^ 2 = (2x) ^ 2
The solution is x = 16sqrt (3) / 15
2x=32sqrt(3)/15
[sqrt stands for radical]

For a right triangle, one acute angle is 56 degrees and the other acute angle is? Degree The title of the fourth grade is

Thirty-four

If the acute angle between the center line and the hypotenuse of a right triangle is 50 degrees, then the degree of the smaller inner angle of the right triangle is______ .

As shown in the figure, ∵ CD is the center line on the hypotenuse of RT △ ABC,
∴CD=AD=DB，
∴∠A=∠ACD，
∵ the acute angle formed by the center line and the bevel edge on the bevel edge is 50 °, that is  BDC = 50 °,
∴∠BDC=∠A+∠ACD=2∠A=50°，
The solution is ∠ a = 25 °,
Another acute angle ∠ B = 90 ° - 25 ° = 65 °,
The degree of the smaller inner angle of this right triangle is 25 degrees
So the answer is: 25 degrees

An acute angle of a right triangle is five times that of the other acute angle?

90°÷(1+5)=15°
The degree of the smaller inner angle is 15 degrees

In a right triangle, the degree of the larger acute angle is twice that of the smaller acute angle Using equations

If the smaller acute angle is x degree, the larger acute angle is 2x degree
X+2X=90
3X=90
X=30
2X=30*2=60
The two acute angles are 30 degrees and 60 degrees, respectively

In a right triangle, if the degree of one acute angle is half of that of the other, what are the degrees of the two acute angles?

Thirty
Sixty
Because a right angle is 90 degrees
The sum of the remaining two is 90 degrees
Let one be x and the other 2x
Then x + 2x = 90 degrees
So x = 30 degrees
So 2x = 60 degrees