If the three sides of a right triangle are three consecutive even numbers, and the area is 24, then the three sides of the triangle are respectively pro,

If the three sides of a right triangle are three consecutive even numbers, and the area is 24, then the three sides of the triangle are respectively pro,

6,8,10

If the three sides of a right triangle are continuous even numbers, its circumference is () A. 12 B. 24 C. 36 D. 48

∵ the three sides of a right triangle are continuous even numbers
The smallest right angle side can be set as X, then the other right angle side is x + 2, and the length of inclined side is x + 4
According to Pythagorean theorem, X2 + (x + 2) 2 = (x + 4) 2
The result shows that X1 = - 2 (omit) x2 = 6
The circumference is 6 + 8 + 10 = 24
Therefore, B

If the three sides of a right triangle are continuous even numbers, then the circumference of the triangle is?

Let the three sides be n-2,2,2 + 2
(n-2)^2+n^2=(n+2)^2
-4n+4+n^2=4n+4
The solution is n = 8, 0
So the three sides are 6, 8, 10. The perimeter is 24

Does a Pythagorean array have a multiple of 4? A multiple of 5

The Pythagorean number is usually a group of positive integers that can form three sides of a right triangle It is found that these Pythagorean numbers are all odd numbers, and nine has never been interrupted since 3. Calculate 0.5 (9-1), 0.5 (9 + 1) and 0.5 (25-1), 0.5 (25 + 1), and according to you

Verification: there are at least even numbers in the Pythagorean array

Because odd + odd = even, odd + even = odd
Therefore, a 2, B 2, C 2 cannot be all odd numbers, so at least one of them is even;
Then a, B, C cannot be all odd, so at least one of them is even
If you don't understand, please follow up. If you solve the problem, please click "select as satisfactory answer"

Observe these Pythagorean strings and input three arrays, guess: for integer Pythagorean, there must be a multiple of what number in Pythagorean? Can you prove it? A right triangle whose three sides are all positive integers is called an integer Pythagorean, in which the values of the three sides are called the triple array of Pythagorean chords. Here are some triangles of Pythagorean chords: (3,4,5); (5,12,13); (7,24,25); (8,15,17)

It is proved that every integer is one of the following four forms: 4m + 1,4m + 2,4m + 3,4m, and their squares are 4N + 1,4n, 4N + 1,4n. Therefore, the numbers of forms 4N + 2 and 4N + 3 cannot be square numbers. First, it is shown that there is at least one even number in the form of a and B, which can not be all odd numbers

If the triangle A.B.C of the triangle ABC satisfies the condition that the square of a + the square of B + the square of C + 338 = 10A + 24B + 26c, find the area of the triangle ABC

∵ A2 + B2 + C2 + 338 = 10A + 24B + 26c

If the triangle A.B.C of the triangle ABC satisfies the condition a square + b square + C square + 338 = 10A + 24B + 26c, try to judge the shape (process) of triangle ABC

∵a²+b²+c²+338=10a+24b+26c ∴[ a²-10a+5²]+[b²-24b+(12)²]+[c²-26c+(13)²]=0 (a-5)²+(b-12)²+(c-13)&#...

The three sides a, B, C of triangle ABC satisfy that the square of a plus the square of B plus the square of C plus 338 equals 10A + 24B + 26c. Find the area of triangle ABC It's urgent———————— There are also the second question on p88 page of the eighth grade mathematics book published by Hebei Education Press

A ^ + B ^ + C ^ + 338 = 10A + 24B + 26c, so a ^ - 10A + B ^ - 24B + C ^ - 26c + 338 = 0, so (a-5) ^ - 25 + (B-12) ^ - 144 + (C-13) ^ - 169 + 338 = 0, so (a-5) ^ + (B-12) ^ + (C-13) ^ = 0, so a = 5, B = 12, C = 13 are a group of Pythagorean numbers, a and B are right angle sides, so the area of triangle is 30 ^ represents square

If the three sides a, B and C of △ ABC satisfy A2 + B2 + C2 + 338 = 10A + 24B + 26c, then the area of △ ABC is () A. 338 B. 24 C. 26 D. 30

From A2 + B2 + C2 + 338 = 10A + 24B + 26c, we can get: (a2-10a + 25) + (b2-24b + 144) + (c2-26c + 169) = 0, that is: (a-5) 2 + (B-12) 2 + (C-13) 2 = 0, a-5 = 0, B-12 = 0, C-13 = 0, and a = 5, B = 12, C = 13, ∵ 52 + 122 = 169 = 132, that is, A2 + B2 = C2, ﹤ C = 90 °, C-13 = 0