How many isosceles right triangles can be cut from a rectangular paper with a length of 5 decimeters and a width of 2 decimeters? In my son's homework, I divide the area of a rectangle by the area of a triangle to get 125. But the answer is no, it's 120. Obviously, it's wrong to divide the area by the area, I thought for a while, the answer is right, but I don't know how to use the formula. I think that the width of 2 decimeters = 20cm, except the side length of the triangle 4cm can be divided, the width can get the side length of five triangles, but when 50 cm is divided by 4 cm, the length of the rectangle can not be fully used

How many isosceles right triangles can be cut from a rectangular paper with a length of 5 decimeters and a width of 2 decimeters? In my son's homework, I divide the area of a rectangle by the area of a triangle to get 125. But the answer is no, it's 120. Obviously, it's wrong to divide the area by the area, I thought for a while, the answer is right, but I don't know how to use the formula. I think that the width of 2 decimeters = 20cm, except the side length of the triangle 4cm can be divided, the width can get the side length of five triangles, but when 50 cm is divided by 4 cm, the length of the rectangle can not be fully used

Two triangles form a square
50 / 4 = 12.5
20/4=5
Round 5 * 12 = 60
60*2=120

A piece of rectangular paper, 7.0 mm long and 6.0 mm wide, is cut into small squares with the same side length and the largest side length. What is the side length? How many pieces can be cut into at least?

7.5=5×1.5
6=4×1.5
So the greatest common divisor is 1.5
So the maximum side length is 1.5 decimeters

Three right triangles with 5 cm, 12 cm and 13 cm in length are shown in Fig. 1. Fold their short right angles to the hypotenuse and coincide with the hypotenuse, as shown in Figure 2. What is the area of the shaded part (i.e. the uncovered part) in Figure 2?

Let de = x cm, according to the area formula of triangle, 1
2AB×DE=1
2BD×AC，
Because AB = 13 cm, AC = 5 cm, BD = bc-cd = bc-de = 12-x (CM),
So the equation: 1
2×13x=1
2（12-x）×5
By solving this equation, x = 10
3，
So de = 10
3 (CM);
So the area of the triangle BDE is 1
2×（13-5）×10
Three
=1
2×8×10
Three
=40
3 (square centimeter),
Forty
3 square centimeter = 1
750 square meters;
A: in Figure 2, the area of the shaded part (i.e. the uncovered part) is 1
750 square meters

For a right triangle with three sides of 5cm, 12cm and 13cm respectively, fold its shortest side in half and coincide with the hypotenuse to calculate the shadow area I haven't learned Tana in the sixth grade of primary school. Please be simple

The shadow part is also a right triangle. One right angle side is the shortest side, i.e. 5cm. The other one needs to use the smallest acute angle sine to calculate. I just calculated that the area is 25 / 3

If you fold the short side of a right triangle that is 5cm, 12cm and 13cm long to coincide with the hypotenuse, then the area of the shadow is equal to three What is the ratio of the area of the triangle ABC? The shadow area is: Triangle EBD In the picture: inside a large triangle, there are triangle EBD, triangle EDA and triangle ADC

So AE = 5, be = 8
So be / BC = de / AC, that is 8 / 12 = de / 5, so de = 10 / 3
Shadow area = 1 / 2 * 8 * 10 / 3 = 40 / 3
Δ ABC area = 1 / 2 * 12 * 5 = 30

For three right triangles with 3 cm 4 cm 5 cm in length, fold their short right angles to the hypotenuse and coincide with the hypotenuse, and find the coincidence part Sorry, the picture can't be typed

First of all, we can see that after the short right angle side of AB is folded to the hypotenuse, a triangle AED which is congruent with the triangle abd appears. Then AB = AE = 3cm, BD = de. we can set the side BD = x, then the side BD = de = x, because BC = 4cm, AC = 5cm

Three right triangles with 5 cm, 12 cm and 13 cm in length are shown in Fig. 1. Fold their short right angles to the hypotenuse and coincide with the hypotenuse, as shown in Figure 2. What is the area of the shaded part (i.e. the uncovered part) in Figure 2?

Let de = x cm, according to the area formula of triangle, 1
2AB×DE=1
2BD×AC，
Because AB = 13 cm, AC = 5 cm, BD = bc-cd = bc-de = 12-x (CM),
So the equation: 1
2×13x=1
2（12-x）×5
By solving this equation, x = 10
3，
So de = 10
3 (CM);
So the area of the triangle BDE is 1
2×（13-5）×10
Three
=1
2×8×10
Three
=40
3 (square centimeter),
Forty
3 square centimeter = 1
750 square meters;
A: in Figure 2, the area of the shaded part (i.e. the uncovered part) is 1
750 square meters

If the ratio of the two right sides of a right triangle is 3:4 and the length of the hypotenuse is 20, then its area is______ .

According to the meaning of the title, let the two right angles be 3x and 4x,
Then (3x) 2 + (4x) 2 = 202,
X = 4, so the two right angles are 12, 16;
One
2×12×16=96，
So its area is 96

The lengths of the two right sides of a right triangle are 4cm and 3cm respectively. If we take the 4cm long right angle side as the axis of rotation, we can get a cone. The volume of the cone is cubic centimeter?

One
3×3.14×32×4，
=3.14×3×4，
=68 (cubic centimeter);
A: the volume of this cone is 37.68 cubic centimeters

The length of the two right sides of a right triangle are 3cm and 4cm respectively, and the oblique side is 5cm long. Its area is () flat The length of the two right sides of a right triangle are 3cm and 4cm respectively, and the length of the hypotenuse is 5cm. Its area is () square centimeter and the height on the hypotenuse is () cm

6 2.4