It is known that the sides to which △ ABC, ∠ a, ∠ B and ∠ C are respectively a, B, C and a: B: C = 13:12:5, is △ ABC a right triangle? Why? Understanding with Pythagorean

It is known that the sides to which △ ABC, ∠ a, ∠ B and ∠ C are respectively a, B, C and a: B: C = 13:12:5, is △ ABC a right triangle? Why? Understanding with Pythagorean

Let a = 13T
Because a: B: C = 13:12:5
So B = 12t, C = 5T
Then B ^ 2 + C ^ 2 = (12t) ^ 2 + (5T) ^ 2 = 144t ^ 2 + 25t ^ 2 = 169t ^ 2 = (13T) ^ 2 = a ^ 2
So the triangle ABC is a right triangle

If the ratio of the two right angles of RT △ is 5:12, then the ratio of height to hypotenuse is () A. 60：13 B. 5：12 C. 12：13 D. 60：169

According to the meaning of the title, two right angles of a right triangle are 5K and 12K respectively,
According to the Pythagorean theorem, the oblique side is
(5k)2+(12k)2=13k，
∵S=1
2•5k•12k=1
2•13k•h，
∴h=60
13，
The ratio of the height on the bevel to the bevel is 60
13：13=60：169．
Therefore, D is selected

Given that the two sides of a right triangle are 7 and 13, and the hypotenuse is C, do you know which two integers C is between

These are two questions. Don't make a mistake
One
13-7

The three sides of a right triangle are 5cm, 13cm and 12cm. The area of this triangle is () square centimeter A. 32.5 B. 60 C. 30 D. 78

12×5÷2，
=60÷2，
=30 (square centimeter),
A: the area of this triangle is 30 square centimeters;
Therefore, C

a: B: C = 5:12:13, is this a right triangle?

Yes, according to the Pythagorean theorem: the square of a + the square of B = the square of C

Given a right triangle hypotenuse C = 21, a right angle side B = 4, find another right angle side a My parents all come here, because the mid-term exam is coming soon. These junior high school level things are not good, so please answer them quickly If you can answer the question, you'd better mark the process and why. I'm short of science and I'm stupid=

Using Pythagorean theorem
a=√﹙21²﹣4²﹚=√﹙441-16﹚=5√17

Given a right triangle, hypotenuse C is 21, a right angle side B is 4, find another right angle side a

Using Pythagorean theorem
a=√﹙21²﹣4²﹚=√﹙441-16﹚=5√17
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Given that a right angle side of a right triangle is 21, find another corner and hypotenuse

Otherwise, the other right angle side is a and the hypotenuse C = radical (a ^ 2 + 21 ^ 2)
If it is an integer solution, then C ^ 2-A ^ 2 = (c + a) (C-A) = 21 ^ 2 = 3x3x7x7
C + a > C-A, so there are four groups
c+a=49,c-a=9 ,c=29, a=20
c+a=63,c-a=7, c=35, a=28
c+a=147,c-a=3,c=75,a=72
c+a=441,c-a=1,c=221,a=220

Junior three mathematics: we know the three sides a, B and C of a right triangle, and the two right angles a and B satisfy the equation Given the three sides a, B and C of a right triangle, and the two right angles a and B satisfy the equation (a ﹣ B ﹣ 2) - 2 (a ﹣ B ﹣ 2) - 15 = 0, we can find the value of hypotenuse C

Right triangle, we can get a 2 + B 2 = C square
The formula is simplified
The fourth power of C - the square of 2C + 1 = 16
(C square - 1) square = 16
C squared - 1 = 4
C squared = 5
C = radical 5
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The length of the hypotenuse of a right triangle Two right angle sides are 14 on one side and 10 on the other

A2 + B2 = C2
Hypotenuse = 6 times root sign 11