As shown in the figure, in the triangle ABC, BC = 8 cm, ad = 6 cm, e and F are the midpoint of AB and AC respectively______ Square centimeter

As shown in the figure, in the triangle ABC, BC = 8 cm, ad = 6 cm, e and F are the midpoint of AB and AC respectively______ Square centimeter

The area of triangle ABC is 8 × 6 △ 2 = 24 (square centimeter);
The area of triangle EBF is 1
4 × 24 = 6 (square centimeter);
Answer: the area of triangle EBF is 6 square centimeter
So the answer is: 6

L in the triangle ABC, ad is perpendicular to BC, CE is perpendicular to AB, ad = 8 cm, CE = 7 cm, AB + BC = 21 cm. What is the area of triangle ABC? This is a graphic problem

Let AB = x, then BC = 21-x
S triangle ABC = 1 / 2 * ad * BC = 1 / 2 * EC * ab
8 * (21-x) = 7 * X
X = 11.2
So s triangle = 1 / 2 * 11.2 * 7 = 39.2

In ABC, the angle of 90 degrees is equal to BC AC is equal to BC, ad is the bisector of the angle BAC, where BC intersects with D de and ab is perpendicular to E. given that AB is equal to 10, find the circumference of the triangle DBE

In this paper, we make an AB in F ∵ AC = BC, ∵ C = 90 ≓ cab = b = 45 ∵ the ∵ D ᚛ C = 90 ∵ cab = b = 45 ∵ the ∵ DF ᙨ AC  AC ? f ∵ AC ? AC ∵ AC ? AC = AC ∵ AC = BC, ? C = C = 90 ? C = C = 90 e c = 90 ? f ﹤ fad = ﹤ ADF ﹥ AF =

If the length of the fold a, B, C is equal to the angle of a, B, C, then the angle is equal to 8

Because the triangle ACD is equal to the triangle ade, so AC = AE = 6cm, CD = De, angle DEA = angle ACD = 90 degrees, because this is RT triangle, AC = 6cm, CB = 8cm, ab = 10cm (according to Pythagorean theorem), be = ab-ae = 4cm, because CD = de CD + DB = 8cm, so de + DB = 8cm, because DEB = 90 degrees, we can get the conclusion by Pythagorean theorem

It is known that AB is equal to 12 cm and BC is equal to 5 cm in the right triangle ABC

This should be discussed in different cases. If ∠ ABC is a right angle, then the area is 30; if ∠ BCA is a right angle, then AC is equal to root 119, and the area is 2.5 times root number 119; if ∠ BAC is a right angle, AC is still equal to root 119, but the area is 6 times root number 119

As shown in the figure, we know that in RT △ ABC, ∠ ACB = 90 °, AC = 4, BC = 3. Take the line where AB edge is located as the axis, rotate △ ABC for one cycle, then the surface area of the geometry obtained is______ .

∵ RT △ ABC, ∵ ACB = 90 °, AC = 4, BC = 3,
∴AB=5，
The height of AB edge is 3 × 4 △ 5 = 2.4,
The surface area of the resulting geometry is 1
2×2π×2.4×3+1
2×2π×2.4×4=16.8π．
So the answer is: 16.8 π

Given a right angle, angle ABC, angle B equal to 90 degrees, AB equal to 6, BC equal to 8, then what is the area ratio of the inscribed circle and circumscribed circle of the right triangle?

Solution: AC = √ (AB ^ 2 + BC ^ 2) = 10
(2) = (2) = (8) = (6) / (10) = (6) = (2) = (6) = (6) = (6) = (6) = (6) = (6) = (6) = (2) = (6) / (6) = (6) = (6) = (6) = (6) =;
Radius of circumscribed circle r = 10 / 2 = 5
Therefore, the area ratio of inscribed circle to circumscribed circle is (π R ^ 2) / (π R ^ 2) = R ^ 2 / R ^ 2 = 4 / 25

In the right triangle ABC, the angle c is equal to 90 °, AC is equal to 6cm, BC is equal to 8cm. The diameter of the three sides is taken as a semicircle, and the area of the shadow part is As the title

Area: = π (3 2) divided by 2 + π (4 2) divided by 2 + π (5 2) divided by 2 + 6 times 8 divided by 2. = 25 π + 7

In the triangle ABC, if the angle B equals 30 degrees, the angle c equals 45 degrees, and BC equals 8, then the area of the triangle is? mathematics

16 (∫ 3-1) sit ad ⊥ BC, divide into two special triangles, find ad

CD is the height on the AB side of the triangle ABC, and CB is the median line of the triangle ADC. It has been known that ad = 10, CD = 6. Find the area of the triangle ABC Thank you, because that's why it's written

According to the meaning of the title, the area of the triangle ADC minus the area of the triangle CBD is required: (10 * 6) / 2 - (5 * 6) / 2 = 15