As shown in the figure, the OAB area of isosceles right triangle is 8 square centimeter

As shown in the figure, the OAB area of isosceles right triangle is 8 square centimeter

3.14×（8×2），
=3.14×16，
=24 (square centimeter);
A: the area of the circle is 50.24 square centimeters

As shown in the figure, if the circumference of right triangle ABC is 24 and ab: BC = 5:3, then AC = () A. 6 B. 8 C. 10 D. 12

Let AB = 5x, BC = 3x, in RT △ ACB,
According to the Pythagorean theorem, the following results are obtained
AC2=AB2-BC2，
AC=
AB2−BC2=
(5x)2−(3x)2=4x，
The circumference of right triangle ABC is: 5x + 4x + 3x = 24, x = 2,
Therefore, AC = 2 × 4 = 8,
Therefore, B

If the circumference of right triangle ABC is 24 and ab ratio AC = 5:3, what is ab?

When AB is an oblique edge, according to Pythagorean theorem,
AB:AC:BC=5:3:4,
The circumference of right triangle ABC is 24, so AB = 5 * 24 / (3 + 4 + 5) = 10,
When AB is a right angle side, according to Pythagorean theorem,
AB^2+AC^2=BC^2
Let AB = 5x, then AC = 3x,
BC=x√（25+9）=x√34,
And the circumference of right triangle ABC is 24, so 5x + 3x + X √ 34 = 24,
x=24/（√34+3+5）,
So AB = 5 * 24 / (√ 34 + 3 + 5) = 120 / (√ 34 + 8) = 32-4 √ 34

The circumference of the right triangle ABC is 24 cm. The length ratio of its three sides is 3:4:5. Find the length of AB, BC and AC

Because the length ratio of the three sides is 3:4:5,
therefore
The three sides are as follows:
24 × (3 + 4 + 5) × 3 = 6cm
24 × (3 + 4 + 5) × 4 = 8 cm
24 × (3 + 4 + 5) × 5 = 10 cm

It is known that the circumference of a right triangle is 2 + √ 6, and the hypotenuse is 2

Let the three sides of a triangle be a, B, C, respectively
∵a+b+c=2+√6,c=2
∴a+b=√6
∵ △ ABC is a right triangle
ν a square + b square = C square
ν C square = [(a + b) square] - 2Ab
That is, 4 = 6-2ab
∴ab=1
∵S△ABC=ab/2
∴S△ABC=ab/2=1/2
A: the area of a right triangle is 1 / 2

The circumference of a right triangle is known to be 2+ 6, the length of the slanted side is 2, and its area is______ .

Let the two right angles be a and B respectively, and the hypotenuse is C,
∵ the circumference of a right triangle is 2+
6, oblique side length 2,
∴a+b+c=2+
6，a+b=
6，
And ∵ C2 = A2 + B2 = 4,
∴ab=1，
∴S=1
2ab=1
2．
So the answer is: 1
2．

Given that the circumference of a right triangle is 2 + √ 6 and the hypotenuse is 2, find the area of the right triangle It's best to use the knowledge of the first half of the second year of junior high school to solve it!

The length of the right angle side is √ 6, and the two sides are a and B respectively
a+b=√6----》(a+B)*(a+b)=6 ——》a*a+b*b+2*ab=6
A * a + b * b = 4 (Pythagorean theorem)
Subtracting AB = 1
Area AB / 2 = 0.5

A triangle with a right angle of 2 has a diagonal perimeter+ 6. Find the area of the triangle

Let the two right sides of a right triangle be x and Y respectively,
From the hypotenuse to 2, the perimeter is 2+
6，
X + y + 2 = 2+
6, that is, x + y=
6①，
According to Pythagorean theorem, X2 + y2 = 22 = 4, 2,
Square the left and right sides of ① to get: (x + y) 2 = x2 + 2XY + y2 = 6,
Substituting ② into: 2XY + 4 = 6, that is, xy = 1,
Then the area of the triangle is s = 1
2xy=1
2．

If the area of a right triangle with the root 5 of 2 times the hypotenuse is 3, then the perimeter of the triangle------

If two right angles are x and y, then
1/2XY=3
X^2+Y^2=(2√5)^2
That is xy = 6
X^2+Y^2=20
(X+Y)^2=20+12=32
X+Y=4√2
So the circumference of the triangle is 2 √ 5 + 4 √ 2

If the circumference of a right triangle is 4 + root 26, and the length of the central line of the hypotenuse is 2, what is the area?

The hypotenuse is 4
Let two right angles be a, B and C, respectively
a+b=√26 ○
A square + b square = 16 ·
The square of formula 0 is a square + b square + 2Ab = 26
Substituting ● into the equation, 2Ab = 10
Then AB = 5
S=1/2ab=0.5*5=2.5