What is sin 75 and sin 15 equal

What is sin 75 and sin 15 equal

 

What is sin75 times sin15? Please take care of it

Is it missing one degree? If not, I will answer
sin75°*sin15°=sin(45°+30°)*sin(45°-30°)=(sin45°*cos30°+cos45°*sin30°)(sin45°*cos30°-cos45°*sin30°)=(sin45°*cos30°)^2-(cos45°*sin30°)^2=1/4

sin75°cos30°-sin15°sin150°=______ .

sin75°cos30°-sin15°sin150°=sin75°cos30°-cos75°sin30°=sin（75°-30°）=sin45°=
Two
Two
answer:
Two
2．

How did sin15 °× cos15 ° = 1 / 2 * sin30 ° evolve

Double angle formula
sin2x=2sinxcosx
So sinxcosx = (1 / 2) sin2x
Here x = 15 degrees
So sin15 °× cos15 ° = (1 / 2) sin30 °

Evaluate sin15 ° * sin30 ° * sin45 ° * sin60 ° * sin75 °

=sin15*sin30*sin60*cos15
=1/2sin30*sin30*sin60
=1 / 4 * 1 / 2 * root 3 / 2
=Radical 3 / 16

Sin45 ° times sin30 ° minus sin45 ° times sin60 ° equals?

Sin30 ° = cos60 °, sin45 ° = cos45 ° sin45 ° * sin30 ° - sin45 ° * sin60 ° = cos45 ° * cos60 ° - sin45 ° * sin60 ° = cos (45 ° + 60 °) = cos105 ° = - cos75 ° (= - sin15 °) (using the formula cos (a + B) = cosa * CoSb Sina * SINB)

(2cos ^ 75 degrees - 1) / (sin75 degrees, cos75 degrees)

The title is (2 (COS ^ 75) ^ 2-1) / (sin75 cos75) = (cos150) / [(sin150) / 2] = 2 / tan150 = - 2 / tan30 = - 2 / (sqrt (3) / 3) = - 2 * sqrt (3) used: 2sinxcosx = = sin (2x) cos (2x) = 2 (cosx) ^ 2-1

（cos75°+sin75°）（cos75°-sin75°）

（cos75°+sin75°）（cos75°-sin75°）
=cos²75º-sin²75º
=cos150º
=cos(180º-30º)
=-cos30º
=-√3/2

Cos squared 35 degrees + cos squared 55 degrees + cos15 degrees cos75 degrees=

Cos squared 35 degrees + cos squared 55 degrees + cos15 degrees cos75 degrees
＝cos^2 35°+sin^2 35°+cos15°sin15°
＝1＋sin30°*1/2
=1+1/4
=5/4

Cos75 squared + cos15 squared + cos75 multiplied by sin15

Original cos? 75 + sin? 75 + cos? 75
=1+(1+cos150)/2
=(6-√3)/4