According to a certain rule, the number 1, - 3,9, - 27,81, - 243,. The nth number can be expressed as___ . Don't use the (n-1) power of - 3, which doesn't make sense. The (1-1) power of - 3 is equal to - 3

According to a certain rule, the number 1, - 3,9, - 27,81, - 243,. The nth number can be expressed as___ . Don't use the (n-1) power of - 3, which doesn't make sense. The (1-1) power of - 3 is equal to - 3

∵ number of columns 1, - 3,9, - 27,81, - 243 ,
The nth number can be expressed as (- 3) ^ n-1
When n = 1, (- 3) ^ 1-1 = (- 3) ^ 0 = 1
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The number of a column arranged in sequence is given: negative 1,2,4,8,16,32 Q: according to the law, what is the nth number?

﹙－1﹚^n×2^﹙n－1﹚

This paper gives the number of a column arranged in sequence: 2, - 4.8, - 16, 32. According to the law, the nth number is calculated and expressed by the formula containing n?

I also rely on my own feelings
The nth power of 2 = - 2 × (the N-1 power of 2)
Can you understand? I don't know how to use symbols in Sogou input method

There is a column of numbers, arranged according to a certain rule: - 1,2-4,8, - 16,32, - 64128,., where the sum of three adjacent numbers is 384

The adjacent numbers are x, - 2x, 4x
Three numbers add up to
3x=384
x=128
So the three numbers are
128,-256,512

There is a regular sequence of - 1, 2, - 16,... - 1 Where the sum of three adjacent numbers is 384______ .

Let the number in the middle be x, then the number in front is - X
2. The number after that is - 2x
According to the meaning of the title, the equation can be formulated: - X
2+x+（-2x）=384
The solution is: x = - 256
The number in front is 128, and the number in the back is 512
So fill in 128, - 256512

There is a column of numbers, arranged according to a certain rule: - 1,2, - 4,8, - 16,32, - 64 Where the sum of three adjacent numbers is 384

Let the number in the middle be - 2 ^ n
2^(n-1)-2^n+2^(n+1)=384
N=8
The three numbers are 128, - 256, 512

1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 + 1 / 32 + 1 / 64 + 1 / 128 = 1-1 / 128 1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 + 1 / 32 + 1 / 64 + 1 / 128 = 1-1 / 128 why are the formulas equal

The left denominator is written as 128 numerator, which means 64 + 32 + 16 + 8 + 4 + 2 + 1 = 127, 127 / 128, the same as the right

Fill in the regular numbers: 1 / 2, 1 / 4, 1 / 8, (), 1 / 128 Hope someone will answer!

Regular filling: 1 / 2, 1 / 4, 1 / 8, (1 / 64) and 1 / 128

1 / 2 + 1 / 4 + 1 / 8 = 1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 = 1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 = 1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 + 1 / 32 + 1 / 64 + 1 / 128 + 1 / 256 = As above. Work out the number and find out the law

1/2+1/4+1/8=7/8
1/2+1/4+1/8+1/16=15/16
1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256= 255/256
Rule: the denominator of the final result is the same as that of the last number, and the numerator is 1

Find the rule 1 / 2, - 1 / 4,1 / 8, - 1 / 16,1 / 32, - 1 / 64. What is the nth number

-The N + 1 power of 1 times the n power of 1 / 2