The absolute value of root 12 - (- 2009) to the power of 0 (1 / 2) to the power of - 1 g root sign 3 - 1

The absolute value of root 12 - (- 2009) to the power of 0 (1 / 2) to the power of - 1 g root sign 3 - 1

The 0 th power of Radix 12 - (- 2009)
=2√3-1
The - 1 power of (1 / 2)
=2
Absolute value g root sign 3 - 1
=2

-The absolute value of 4 - the - 2nd power of radical 9 + 3 - the 0 th power of (2009-2 parts π)

-The absolute value of 4 - the - 2nd power of radical 9 + 3 - the 0 th power of (2009-2 parts π)
=4-3+1/9-1
=1/9

(π - 2012) 0 power + (1 / 2) - 1 power + root sign 12 + absolute value root 3 - 2

=1+2+2√3+2-√3
=5+√3

The absolute value of root 4 / 9 - (- radical 2) to the power of 0 + (root 3-radical 2) - 1 power + - radical 3

Original formula = 2 / 3-1 + 1 / (√ 3 - √ 2) + √ 3
=-1/3+(√3+√2)/(3-2)+√3
=-1/3+√3+√2+√3
=-1/3+2√3+√2

The absolute value of - 8-1-radical 2 under the 0 th power of (π - 3.14) + the root sign 2 of the third power

Original formula = 1 + √ 2 + (- 2) - (√ 2-1)
=1+√2-2-√2+1
=0

Known If a + 2 + | B − 1 | = 0, then the value of (a + b) 2007 is______ .

A kind of
a+2+|b−1|＝0，
Qi
a+2＝0
b−1＝0 ，
The solution
a＝−2
b＝1 ，
∴（a+b）2007=（-2+1）2007
=-1，
So the answer is - 1

The 2013 power of two plus three multiplied by the 2013 power of two minus three

=【（2+√3）（2+√3）】^2013
=【2²-（√3）²】^2013
=（4-3）^2013
=1^2013
=1

If the root number 2014 minus 1 / 2013 equals m, then the fifth power of M minus 2 times, the fourth power of M minus 2013 times, and the third power of M is equal to

M = 2013 / (√ 2014-1) = 2013 × (√ 2014 + 1) / (√ 2014-1) × (√ 2014 + 1) = √ 2014 + 1 original formula = m (m-2m-2013) = m [(m-1) - 2014] = m [(√ 2014 + 1-1) - 2014] = m [2014-2014] = 0

If (2a + 3) 2 and If B − 2 is opposite to each other, then ab= ___ .

∵ (2a + 3) 2 and
B-2 is opposite to each other,
∴（2a+3）2+
b-2=0，
Qi
2a+3=0
b-2=0 ，
The solution
a=-3
Two
b=2 ，
Qi
Ab=
(-3
2)2=3
2．
So the answer is 3
2．

If a and B satisfy | cubic root a + 1 | + radical B-2 = 0, then what is the cube root of B power of a?

Because if a and B satisfy | cubic radical a + 1 | + radical B-2 = 0
So | the third root a + 1 = 0 | and the radical B-2 = 0
So the third root sign a + 1 = 0, the root sign B-2 = 0
So a = - 1, B = 2
So the B power of a is (- 1) ^ 2 = 1
So the cube root of B power of a is 1