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Given that a real number a satisfies | 2007-a | + root sign A-2008 = a, then the square value of A-2007 is () a.2006 b.2007 c.2008 d.2005
According to the definition field, the square value of a (2008 A-2007 + Radix A-2008 = a = 2008 + 2007 ^ 2 A-2007) is selected as C in 2008
Simplification: the absolute value of Radix 6-radix-2 + the absolute value of radix-2-retain the exact value
The absolute value of root 6-radical 2 + 1-absolute value of radical 2,
=√6-√2+√2-1
=√6-1
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Simplify absolute value 1-radical 2 + absolute value radical 2-radical 3 + absolute value radical 3-radical 2
|1-√2|+|√2-√3|+|√3-√2|
=-（1-√2）-（√2-√3）+（√3-√2）
=2√3-√2-1
If the point P (a + 2,3-a) is in the first quadrant, then the absolute value of 2a-7 is square root a + 4A + X=
In the first quadrant
a+2>0,a>-2
3-a>0,a
When a ≤ 1 / 2, the absolute value of 1-4a + 4A 2 + 2a-1 under the root sign is simplified
Absolute value of 1-4a + 4A 2 + 2a-1 under root sign
=The absolute value of √ (2a-1) 2 + 2a-1
=Absolute value of √ (2a-1) (2a-2)
=√2(1-2a)(1-a)
If x ∈ [- π / 2, π / 2], find the maximum and minimum of the function f (x) = SiNx + radical 3 * cosx
x∈[-π/2,π/2],
f(x)=sinx+√3*cosx
=2(1/2*sinx+√3/2*cosx）
=2sin（x+π/3）
-π/6
If x belongs to [- π / 2,0], then what is the minimum value of cosx for the function f (x) = cos (x + π / 6) - cos (x - π / 6) + three times the radical?
F (x) = cos (x + π / 6) - cos (x - π / 6) + SQR (3) * cosx = cosxcos π / 6-sinxsin π / 6-cosxcos π / 6-sinxsin π / 6 + SQR (3) * cosx = - SiNx + SQR (3) cosx = - 2Sin (x - π / 3) because x ∈ [- π / 2,0], so (x - π / 3) ∈ [- 5 π / 6, - π / 3], so the minimum value of the function
The minimum positive period sum of the function y = sin 2 (π x + 2) is
It can be transformed into
=[1-cos(2πx+4)]/2
Minimum positive period T = 2 π / 2 π = 1
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Find the period, maximum value and minimum value of the function f (x) = cos? X + 2 √ 3 sinxcosx sin? X
f(x)=cos²x+2√3 sinxcosx-sin²x
=cos2x+√3sin2x
=2 [1/2cos2x+√3/2sin2x]
=2(sinπ/6cos2x+cosπ/6sin2x)
=2sin(2x+π/6)
therefore
Period = 2 π / 2 = π
Max = 2
Minimum = - 2
The period and minimum value of the function y = sin? X-cos? X are respectively?
First of all, we should remember an important trigonometric function formula: the angle doubling formula. There are three formulas for the angle doubling: sine, cosine and tangent. Among them, sin (2x) = 2sinx · cosxcos (2x) = cos 2x - sin? Xtan (2x) = 2tanx / (1-tan? X). Thus, y = sin? X-cos? X can be changed into y = - (cos
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