Find the cube root: 10 to the minus 6 power, root 10 to the minus 12 power

Find the cube root: 10 to the minus 6 power, root 10 to the minus 12 power

1. The cube root of 10 to the negative 6th power is equal to the negative 2nd power of 10;
2. The 12th power of Radix 10 is equal to the 6th power of 10

-The square of 1 + the cubic root of (- 2) * 1 / 8-27 * | - 1 / 3 | + 2 divided by 4 under the root sign

-The square of 1 + the cubic root of (- 2) * 1 / 8-27 * | - 1 / 3 | + 2 divided by 4 under the root sign
=-1-8x1/8-3x1/3+2÷2
=-1-1-1+1
=-2
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The absolute value of radical 3-2 + the cube root of root 3 + negative 8

The original formula = | 3-2 | + 2 √ 3 + 3 √ - 8
=2-√3+2√3-2
=√3

It is known that the absolute value of a is the cube root of 2, the opposite number of radical B is 0, and C is the cube root of negative one Find the cube of a + the cube of B + the cube of C

|a|=2
B=0
c=-1
When a = - 2
a3+b3+c3=-8-1=-9
When a = 2
a3+b3+c3=8-1=7

How to calculate the 2006 power of 2 + 1 times the 2005 power of 2-1 under the root

The 2006 power of 2 + 1 under the root sign times the 2005 power of 2-1 under the root sign
=The 2005 power of (2 + 1 under the root) times the 2005 power of (2-1 under the root)
=The power of (2 + 1) × [(2 + 1) × (2-1)] in 2005
=The power of (2 + 1) × (2-1) to the power of 2005
=(under radical 2 + 1) × 1
=2 + 1 under radical
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(root number 6 + 1) 2008 times - 2 times (root number 6 + 1) 2007 times - 5 times (root number 6 + 1) 2006 times + 2006 times

(root 6 + 1) 2008 times - 2 × (root 6 + 1) 2007 times - 5 × (root 6 + 1) 2006 times + 2006 = (root 6 + 1) 2006 times × [(root 6 + 1) - 2 × (root 6 + 1) - 5] + 2006 = (root 6 + 1) 2006 times × [6 + 2 × root 6 + 1-2 × root 6-2-5] + 2006 = (root 6 + 1 + 1-2 × root 6-2-5] + 2006 = (root 6 plus

If B = the square of root 1-2a plus root 2a-1, then what is the power of (a + b) in 2006?

Guess equal to 1

Given the square of a + A + 1 = 0, find the 2008 power of a + the 2007 power of a + the 2006 power of A

Extract common factor A ^ 2008 + A ^ 2007 + A ^ 2006 = a ^ 2006 (a ^ 2 + A + 1) = a ^ 2006 * 0 = 0

The power of 2009 multiplied by the power of 2008

(√3-2)^2009×(√3+2)^2008
=(√3-2)(√3-2)^2008×(√3+2)^2008
=(√3-2)[(√3-2)(√3+2)]^2008
=(√3-2)(3-4)^2008
=(√3-2)*(-1)
=2-√3

Given that X and y are real numbers, and the square root of (x + Y-1) and the root sign (2x-y + 4) are opposite to each other, find the square root of the cube of X + y

According to the meaning of the title: (x + Y-1) ^ 2 + radical (2x-y + 4) = 0
So x + Y-1 = 0 2x-y + 4 = 0
The solution is x = - 1, y = 2
Bring in the root sign (x ^ 2 + y ^ 3)
=Radical (9)
=3