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Cube root minus 2 and 27 times 10 =? Urgent
Cube root minus 2 and 27 / 10 = cube root minus 27 / 64 = 4 / 3
The absolute value of 98 / 125 of the root of negative cubic minus 1
Negative cubic root 125 = - 5
The root of negative cubic root is 98 of 125 = - 5 / 98
Negative third power root 125 times 98 minus 1 = - 103 / 98
The absolute value of the root of the negative third power is 98 / 125 minus 1 = 103 / 98
The zero power of (0 - π) - the absolute value of 8 + (3-2 under the root sign)
=1-2+2-√3
=1-√3
(Radix 2-1) 2011 power X (Radix 2 + 1) what is the power of 2010?
(root 2-1) 2011 power X (root 2 + 1) 2010 power
=The 2010 power of (Radix 2-1) × [(Radix 2-1) × (Radix 2 + 1)]
=The 2010 power of (root 2-1) × (2-1)
=(radical 2-1) × 1
=Radical 2-1
(root 3 + 2) 2010 times (root 3-2) 2011
The original formula = (root 3 + 2) 2010 power * (root 3-2) 2010 power * (root 3-2)
=((root 3 + 2) * (root 3-2)) 2010 power * (root 3-2)
=1 to the 2010 power * (root 3-2)
=Radical 3-2
Let a = root 7 + root 6, B = root 7 - root 6, then what is the 2010 power of a multiplied by the 2011 power of B?
A ^ 2010 * B ^ 2011 = (AB) ^ 2010 * b = (7-6) ^ 2010 * b = radical 7-6
What is the 2012 power of (root 2 - root 3) times the 2011 power of (root 2 + root 3)? The whole process
This algorithm can use the power algorithm, and the square difference formula is needed in the middle
The 2012 power of (root 2 - root 3) times the 2011 power of (root 2 + root 3)
=The 2011 power of (root 2 - root 3) * (root 2 - root 3) times the 2011 power of (root 2 + root 3)
=The 2011 power of (Radix 2-radix 3) * [(Radix 2-radix 3) times (Radix 2 + Radix 3)]
=The 2011 power of (root 2 - root 3) * [2-3]
=(radical 2-radical 3) * (- 1)
=Radical 3-radical 2
What is the 2011 power of (2 + root 3) times the 2012 power of (2 minus root 3)
The 2011 power of (2 + root 3) multiplied by (2 minus root 3) 2012 = [(2 + root 3) times (2 minus root 3)] 2011 power * (2 minus root 3) = 1 ^ 2011 * (2 minus root 3)) = 2 minus root 3
If M is equal to 2011 divided by 2012 minus 1 under the root sign, then the fifth power of M minus the fourth power of 2m minus the third power of 2011m
M = 2011 / (√ 2012-1) = √ 2012 + 1 then: M-1 = √ 2012, the square of both sides of the equal sign is: (m-1) = 2012, that is, m-2m-2011 = 0; therefore, m ^ 5-2m ^ 4-2011m ^ 3 = m ^ 3 (m-2m-2011) = 0
Given that M is equal to (Radix 2012) - 1 / 2011, then the value of m to the 5th power of - 2m to the 4th power of - 2011m to the 3rd power is
M = 2011 / (√ 2012-1) = 2011x (√ 2012 + 1) / [(√ 2012-1) (√ 2012 + 1)] = 2011x (√ 2012 + 1) / (2012-1) = √ 2012 + 1; substituting the following formula m ^ 5-2m ^ 4-2011m ^ 3 = (m-2m-2011) XM ^ 3 = [(m-1) - 2012] XM ^ 3 = [(√ 2012) - 2012] XM ^ 3 = 0
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