Given that the real number x, y satisfies the root sign 2x-3y-1 + | x-2y + 2 |. Find the square root of (5 / 2) x - (4 / 5) y

Given that the real number x, y satisfies the root sign 2x-3y-1 + | x-2y + 2 |. Find the square root of (5 / 2) x - (4 / 5) y

√(2x-3y-1)+|x-2y+2|=0
The sum of the square root of arithmetic and the absolute value term is 0, and the sum of them is 0, respectively
2x-3y-1=0 (1)
x-2y+2=0 (2)
(1)-(2)×2
y-5=0
Y = 5, substituting (2)
x=2y-2=10-2=8
±√[(5/2)x-(4/5)y]
=±√[(5/2)×8-(4/5)×5]
=±√(20 -4)
=±√16
=±4

Given the absolute value of x-2y-3 + 2x-3y-5 = 0, find the square root of x-8y?

Root x-2y-3 + absolute value 2x-3y-5 = 0
therefore
x-2y-3=0
2x-3y-5=0
The solution
x=1,y=-1
√x-8y
=√1+8
=3
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If the absolute value of X + 2y-5 + 2x-y-5 under the root sign = 0, the square root of X + y is the absolute value of 2x-y + 5 Sorry for typing the wrong number. The title is "if the absolute value of X + 2y-5 + 2x-y-5 under the root sign = 0, find the square root of X + y is the absolute value of 2x-y-5

The absolute value of X + 2y-5 + 2x-y-5 under the radical sign = 0
∴﹛x+2y-5=0
2x-y-5=0
The solution is x = 3, y = 1
∴x+y=3+1=4
The square root of X + y is ± 2

If 2X-4 = 0 under the absolute value + root sign of x-2y, find the square root of X + y RT, to accurately process, root can't be typed as I do. Just wait

|X-2y | + root sign 2X-4 = 0
|x-2y|=0
2X-4 = 0 under radical
2x-4=0
X=2
x-2y=0
y=1/2x=1/2*2=1
The square root of X + y = ± radical 2

Under the radical sign (a to the fifth power + 2a to the cube, B to the square + AB to the fourth power

Under the radical sign (a to the fifth power + 2a to the cube, B to the square + AB to the fourth power
=Under the radical [a (the 4th power of a + the 4th power of 2A 2 B 2 + the 4th power of B)]
=Under the radical sign a

The square of root 3 + (- 4) - cube root - 1 / 64 + root 1 and 9 / 16 * (- 2) - the 2004 power of (- 1)

The original formula = √ 3? + 4? - cube root (- 1 / 4) 3 + √ (5 / 4) 2 × (- 2) 3 - 1
=3+16-（-1/4）+5/4×（-8）-1
=33/4

If the square of the root B-27 + (a + 8) is 0, find the value of the third root a-the third root B

Square of radical B-27 + (a + 8) = 0
b-27=0,a+8=0
b=27,a=-8
Three times root A-3 times root B = - 2-3 = - 5

If the square of root a + 8 and (B-27) are opposite to each other, find the value of cubic root a-cubic root B

Title:
(a + 8) + (B-27) 2 = 0, find the value of cubic root a - cubic root B
Since √ (a + 8) and (B-27) 2 are non negative numbers, according to the meaning of the title, there must be:
√(a+8)=0
(b-27)²=0
The solution is as follows:
a=-8
b=27
So:
Cubic radical a-cubic radical B
=-2-3
=-5

If the square of the root sign (a + 8) and (B-27) are opposite to each other, find the square root of 3 √ (a) - 3 √ (b)

According to the fact that the square root and square are both nonnegative
a+8=0
b-27=0
The solution
a=-8
b=27
3√（a）-3√（b）=-2-3=-5

Radical 27 cubic meters Why is the cube root of Radix 729 3 not plus or minus 3? What is the cube root of Radix 729 a plus minus 9 B plus or minus 3 C3 D Radix 3

If the root sign is simple, the root sign 27 is plus or minus 3
But if it is a cube root, it depends on the number in the root sign. If it is positive 27, the cube root is positive 3; if it is negative 27, the result is negative 3