3 if x and y are real numbers, and the absolute value of (x + 1) plus (radical y minus one) equals 0, then the value of (Y / x) to the power of 2013 is?

solution
/x+1/+√y-1=0
∵/x+1/≥0
√y-1≥0
∴x+1=0,y-1=0
∴x=-1,y=1
∴(x/y)^2013
=(-1/1)^2013
=-1

Given that x = half (root 7 + root 5) and y = half (root 7 - root 5), find the square of the algebraic expression X - XY + y

x+y=(√7+√5+√7-√5)/2=√7
xy=(7-5)/4=1/2
x+y=√7
The square has x 2 + 2 x y + y 2 = 7
Subtract 3xy from both sides
x²-xy+y²=7-3/2=11/2

Given that x = radical 2 + 1, y = radical 2-1, find the square of the algebraic expression X - XY + y

The square of (root 2 + 1) equals 2 + 1 + 2 root 2
In the same way
Finally it's five

If x − y = 2−1，xy＝ Then the value of the algebraic expression (x-1) (y + 1) is equal to 2______

（x-1）（y+1）
=xy+x-y-1
=xy+（x-y）-1
Let x − y =
2−1，xy＝
Substituting 2 into the above formula, we can get:
=
2+
2-1-1
=2
2-2
So the answer is 2
2-2

Given that x = 2 + 1% of the root 2-1, y = 2-1 of the root 2 + 1, find the value of the algebraic formula x ^ 2-xy + y ^ 2

X = 2 + 1% root 2-1, y = 2-1% root 2 + 1
X ^ 2 = (root 2-1) ^ 2 = 3-2 radical 2
XY=1
Y ^ 2 = (radical 2 + 1) ^ 2 = 3 + 2 radical 2
X ^ 2-xy + y ^ 2 = 3-2 root sign 2-1 + 3 + 2 root sign 2 = 5

If the real number x, y satisfies the radical sign X-2 + (3-y) ^ 2 = 0, then the value of the algebraic formula xy-x is

If one is greater than 0, the other is less than 0
So both are equal to zero
So X-2 = 0, 3-y = 0
x=2,y=3
So xy-y = 6-3 = 3

x. If y is a real number and satisfies that (root x + y minus 4) plus (root x minus y minus 2) equals 0, find the value of the algebraic radical XY

If one is greater than or equal to 0, the other is less than 0
So both are equal to zero
So x + y-4 = 0
x-y-2=0
Add up
2x-6=0
X=3
y=4-x=1
So √ xy = √ 3

Let x = root three minus one-half, y = root three plus one-half, find the value of the algebraic formula x + y of x2 + XY + y well Let x = 1 / √ 3-2, y = 1 / √ 3 + 2, find the algebraic formula x2 + XY + Y2 / x + y Do you understand

x＝1/﹙√3－2﹚＝﹣2－√3y＝1/﹙√3＋2﹚＝2－√3xy＝﹙2－√3﹚﹙﹣2－√3﹚＝﹣1x＋y＝﹣2－√3＋2－√3＝﹣2√3∴ ﹙x²＋xy＋y²﹚/﹙x＋y﹚＝[﹙x＋y﹚²－xy]/﹙x＋y﹚＝[﹙﹣2√3﹚²＋1]/...

It is known that x − 1 = 3. Find the value of the algebraic formula (x + 1) 2-4 (x + 1) + 4

The original formula = (x + 1-2) 2
=（x-1）2，
When x − 1 =
At 3:00,
Original formula=（
3)2=3．

What is the minimum value of the root sign (x square + 4) + root sign [(12-x) square + 9]?

Original formula = sqrt [(x-0) ^ + (0-2) ^ 2] + sqrt [(12-x) ^ 2 + (3-0) ^ 2]
This is equivalent to the minimum of the sum of distances from a point (x, 0) to a point (0,2) and a point (12,3) on the x-axis
As long as the graph is drawn, we know that the minimum value is equal to the distance between point (0, - 2) and point (12,3)
That is, sqrt (12 ^ 2 + 5 ^ 2) = 13
If you feel satisfied, give some points to show encouragement!

3 if x and y are real numbers, and the absolute value of (x + 1) plus (radical y minus one) equals 0, then the value of (Y / x) to the power of 2013 is?