If a, B, C are the three sides of the triangle ABC, simplify: radical (a + B + C) ^ 2 - radical (a-b-c) ^ 2 + radical (b-c-a) ^ 2-radical (C-A-B) ^ 2 Big brother, big sister, thank you very much~ Who can figure out I give 5

If a, B, C are the three sides of the triangle ABC, simplify: radical (a + B + C) ^ 2 - radical (a-b-c) ^ 2 + radical (b-c-a) ^ 2-radical (C-A-B) ^ 2 Big brother, big sister, thank you very much~ Who can figure out I give 5

The original formula = | a + B + C | - | a-b-c | + | b-c-a | - | C-A-B|
∵a>0,b>0,c>0
∴a+b+c>0,∴|a+b+c|=a+b+c
∵ a, B, C are the three sides of the triangle ABC, ᙽ B + C > A, C + a > b, a + b > C (the sum of the two sides of the triangle is greater than the third side)
∴a-b-c

If the opposite number of a is equal to itself, then the absolute value of the square + 1 of 3a-27 + 2A under the cubic root sign=

The opposite number of a is equal to itself
A=0
The absolute value of the square + 1 of 3a-27 + 2A under the cubic root sign
=－3＋1
=－2

Known: the square of root 3a-b + | a - 49| / root a + 7 = 0, find the value of real numbers a and B Note: surfing p35 during the seventh grade holiday

The expressions on the left and right of the plus sign are greater than or equal to 0
And the sum is 0
So it's all equal to zero
therefore
3a-b=0
a^2-49=0
But a + 7 ≠ 0
That is, a ≠ - 7
So a = 7
b=3a=21
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Given the radical x-4 + radical 4-x + 3 > y, simplify the absolute value of y-x-y-5 Specific steps, 3Q

√(x-4)+√(4-x)+3>y
Because x-4 > = 0 4-x > = 0
So x = 4
Y

If 3 Homework help users 2017-09-23 report Use this app to check the operation efficiently and accurately!

3-x<0
x-6<0
x+4>0
So the original formula = | 3-x | + | X-6 | + | x + 4|
=x-3+6-x+x+4
=x+7

When 1 is less than x less than 3, the absolute value of 1-x + the square of root sign (x-3) is simplified

1＜x＜3
The absolute root of (x-1) of (x-1)
= x-1+3-x
= 2

Simplify the square of absolute value (1-x) + Radix 4-4x + X

The original formula can be reduced to absolute value X-1 + absolute value X-2
In the first case, when x is less than 1, the original formula = 1-x + 2-x = 3-2x
In the second case, when x is greater than 1 and less than 2, the original formula = X-1 + 2-x = 1
In the third case, when x is greater than 2, the original = X-1 + X-2 = 2x-3

Given 0 < x < 3, reduce the absolute value of root sign (2x-1) ^ 2-x-5

Given that 0 < x < 3, then: 0 < 2x < 6 and - 5, so: - 1 < 2x-1 < 5
Therefore, when 0 ≤ 2x-1 < 5, i.e. 1 / 2 ≤ x < 3, the absolute value of root sign (2x-1) ^ 2 - (X-5) is 2x-1 - (5-x) = 3x-6;
When - 1 < 2x-1 < 0, it is 0
Homework help users 2017-09-25
report

If formula The result of (x − 1) 2 + | x − 2 | reduction is 2x-3, then the value range of X is______ .

(x−1)2+|x−2|=2x-3，
x≥2，
So the answer is: X ≥ 2

If the square of the root sign (x-1) is X-1, then the value range of X is?; 2. If the absolute value of X-5 is known plus the root sign y-6 = O If the square of the root sign (x-1) equals X-1, then the value range of X is?; 2. If the absolute value of X-5 plus the root sign y-6 = O, the perimeter of the staring triangle with X and y as the length of both sides is?; 3. The absolute value of A-1 + the square of (B + 3) + the root sign C + 5 = 0, then the square root of ABC is?

1. It must be X-1 ≥ 0 x ≥ 1
2. The condition of satisfying the above formula is
x-5=0 y-6=0
The solution is x = 5, y = 6
Perimeter = 2 * 5 + 6 = 16 or 2 * 6 + 5 = 17
The condition is satisfied
a-1=0 b+3=0 c+5=0
The solution is a = 1, B = - 3, C = - 5
So √ (ABC) = √ 15