Find the reciprocal of the negative radical 11, the reciprocal of 27 / 8, 3 - π,

Find the reciprocal of the negative radical 11, the reciprocal of 27 / 8, 3 - π,

The reciprocal of negative radical 11
-1/√11=-(√11)/11
Third root: 27 / 8
=³√(3³)/(2³)
=3/2
Reciprocal of 3 - π
1/(3-π)
If additional questions are added,

The reciprocal of minus 27 of the third root sign is The opposite number of the third root sign 9 is 4（2X-1）²=25 X= The square root of a good 16 X=

The reciprocal of the third root minus 27 is: - 3
The opposite number of the third root sign 9 is: - 3 √ 9
4（2X-1）²=25
X=1/2±5/4
The square root of a good 16
X= 2

Cubic root 1000 = 10 cubic root 1 = 1 cubic root 0.001 = 0.1 cubic root 0.00000 1 = 0.01 What kind of rules can you find out through the above? Describe them in your own language

Cubic root x ^ 3 = X
The third root of a cubic number is itself
[questions are welcome]

(LG root 27 + LG8 LG root 1000) / LG1, 2

（lg√27+lg8-lg√1000）/lg1.2
=(3lg3/3+3lg2-3lg10/2)/lg1.2
=3/2(lg3+2lg2-lg10)/lg1.2
=3/2lg1.2/lg1.2
=3/2

Simplification: (root 5 + root 3 + root 2) x (root 5 minus 2 times root 3 + root 2)

(root 5 + root 3 + root 2) x (root 5 minus 2 times root 3 + root 2)
=[(√5+√2)+√3][(√5+√2)-2√3)]
=(√5+√2)^2-√3(√5+√2)-6
=1+2√10-√15-√6

3 and radical 5 minus | - 3 and radical 5 | + 2 and radical 3 -- 2 and radical 3

6 and radical 5

2 minus the reciprocal of root 3

1/(2-√3)=2+√3/2²-(√3)²=2+√3

It is known that a, B are reciprocal of each other, C and D are opposite to each other. Find the value of 3AB cubic radical AB + radical C + D + 1

∵ a, B are reciprocal, C and D are opposite
∴ab=1,c+d=1
ν (1) 3AB - cubic root sign (AB) + root sign (c + D) + 1
=3-1+1+1=4
(2) 3AB - cubic root sign (AB) + root sign (c + D + 1)
=3-1+√2
=2+√2

If AB is opposite to each other and CD is reciprocal to each other, then the root sign a ^ 2 + B ^ 2-3 times root sign (CD) 3 = ()

Because a and B are opposite numbers to each other, a + B = 0, CD is the reciprocal of each other, so CD = - 1. Therefore, the cube root of a 2 + B 2 - (CD) 3 = 2 a 2 + 1 = 2 B 2 + 1

It is known that a and B are reciprocal of each other, C and D are opposite numbers to each other. Find AB under - cubic root sign + C + D + 1 under root sign

∵ A and B are reciprocal, ᙽ a = 1 / b
Thus, ab = (1 / b) B = 1
∵ C and D are opposite numbers, ᙽ C = - D
Thus, C + D = - D + D = 0
-[³√(ab)]+√(c+d+1)
=-(³√1)+√(0+1)
=-1+1
=0