What is the third power of the cube root of minus 12

What is the third power of the cube root of minus 12

(³√-12)³
=（³√-12）×(³√-12)×(³√-12)
=－12
（³√a）³＝a

2 root 3 × cube root 1.5 × 6 power root 12

Original formula = 6 times √ 27x6 times √ 2.25x6 times √ 12
=729 times
=The sixth power of power 6 √ 3
=3
If there are any new questions, please do not send them in the form of follow-up questions. Please send them to me for help or send the link address of questions at the follow-up office,

If (radical 2-x) - (radical X-2) - y = 6, find the cube root of the x-th power of Y

2-x≥0,x-2≥0
x≤2,x≥2
∴x=2
∴y=-6
y^x=(-6)^2=36
The cube root of the x power of y = 3 √ 36

Square of root 3 + 4 * (minus half) - cube root of 2 + cube root of 27 (2) (root 3 + root 2) - root 2

(1) The original formula = 3-2-8 + 3 = 4; (2) the original formula = radical 3

(- 2) + radical (- 4) quadratic + cube root (- 4) cubic multiplication (- 1 / 2) quadratic root 27

(- 2) + radical (- 4) quadratic + cube root (- 4) cubic multiplication (- 1 / 2) quadratic root 27
-2 + 4 + 4 * quarter - 3
-2+4+1-3=0

3 / cube root of root 3-8 - 0 power of (root 2-2010) + root [(square of root 3-2)] Please send it before 11:00,

2√3-1

What is the cube root of negative radical 8? It's not - 2. It means the square root of the arithmetic square root of 8

The cube root of negative radical 8 is - √ 2

Given that the reciprocal of a is [- 1 / 2 of the root], the opposite number of the root B is 0, and C is the cube root of - 1, find a ^ 2 + B ^ 2 + C ^ 2

1/a=-√1/2 =-1/√2 a=-√2
-√b=0,b=0
c^3=-1,c=-1
a^2+b^2+c^
=(-√2)^2+0^2+(-1)^2
=2+0+1
=3

The negative first power of root 2 times root 8

（√2）^-1*√8
=1/√2*√8
=√2/2*√8
=√16/2
=4/2
=2

(3 under the root) + 2) divided by 2007 times of ((3 under the root) + 2)?

(√3+2)^2006/[(√3-2)^2007]
=(√3+2)^2006/[(√3-2)^2006]*[1/(√3-2)]
=[(√3+2)/(√3-2)]^2006*[1/(√3-2)]
=[-(√3+2)^2]^2006*[1/(√3-2)]
=(√3+2)^4012*[-(√3+2)]
=-(√3+2)^4013.