Given that / a-radical 2 / + B? - 2b + 1 = 0, find the value of a ~ quartic - a? B

Given that / a-radical 2 / + B? - 2b + 1 = 0, find the value of a ~ quartic - a? B

|A - √ 2 | B | - 2b + 1 = 0, that is | a - √ 2 | + (B-1) ° = 0

Known: root A-1 + (ab-2) 2 = 0 Find: 1 / (a + 1) (B + 1) + 1 / (a + 2) (B + 2) + +1/（a+2007）（b+2007）+1/（a+2008）（b+2008）.

Root number A-1 + (ab-2) 2 = 0
So we have A-1 = 0 and ab-2 = 0
A = 1, B = 2
Then (1 + 1) (b) + / (a) + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1/（a+2007）（b+2007）+1/（a+2008）（b+2008）=1/2*3+1/3*4+.+1/2009*2010
=1/2-1/3+1/3-1/4+.+1/2009-1/2010
=1/2-1/2010
=502/1005

Given that the absolute value + (radical B + 2) of (A-3) is equal to 0, find a + 2B

a=3 b=-2
a+2b=3+2(-2)=-1

Given that the real numbers a, B, C satisfy the square of 1 / 2 | A-B | + root sign 2B + C + (C-1 / 2) = 0, find the value of a (B + C); Supplement: 1. Given that y = root 2x-1 + Radix 1-2x + 1, find the value of x ^ y: 2. Given that the decimal part of M = Radix 5 + 1 is B, find the value of radical (m-1) (B + 2)

The square of 1 / 2 | A-B | radical 2B + C + (C-1 / 2) is 0;
a-b=0;
2b+c=0;
c-1/2=0'
a=-1/4,b=-1/4.c=1/2
(a(b+c)=-1/4(-1/4+1/2)=-1/16
Supplementary part“
2x-1>=0;
-2x+1>=0;
x>=1/2;x

It is known that a, B and C satisfy 2 | A-1|+ 2b+c+c2-c+1 4 = 0. Find the value of a + B + C

∵2|a-1|+
2b+c+c2-c+1
4=0．
That is, 2 A-1|+
2b+c+（c-1
2）2=0．
∴a-1=0，2b+c=0，c-1
2=0，
∴a=1，c=1
2，b=-1
4，
∴a+b+c=5
4．

On the contrary, the reciprocal of the square of a, B and 2b is the reciprocal of the square of a and B

Real numbers a and B are opposite to each other,
a+b=0
c. D is reciprocal to each other,
cd=1
The absolute value of M is 4
The square of 2A radical 4cd-m + 2B
=2 (a + b) -√ cd-m squared
=0-1-16
=-17

Given the set a = {- A, A2, AB + 1} and B = {- 3} A3 ，a a. If the elements in 2B} are the same, find the values of real numbers a and B

It is known that a = {- A, a, AB + 1}, B = {- A, 1, 2b},
∵ the elements a and B are the same,
Qi
a＝1
AB + 1 = 2B or
a＝2b
ab+1＝1 ，
The solution
a＝1
B = 1 or
a＝0
B = 0 is not consistent with the meaning of the question, so it is omitted;
So the answer is: a = 1, B = 1

Given the set a = {a, a + B, a + 2B}, B = {a, AC, ac2}. If a = B, find the value of real number C

if
a+b＝ac
a+2b＝ac2 ⇒a+ac2-2ac=0，
So a (C-1) 2 = 0, that is, a = 0 or C = 1
When a = 0, the elements in set B are all 0, so they are omitted;
When C = 1, the elements in set B are the same, so it is omitted
if
a+b＝ac2
a+2b＝ac ⇒2ac2-ac-a=0．
Because a ≠ 0, 2c2-c-1 = 0,
That is (C-1) (2C + 1) = 0
And C ≠ 1, so only C = - 1
2．
In conclusion, C = - 1
2．

The absolute value of x-radical 2 = root 10 find the real number x Yes, just like I thought, the side said it was wrong

|X-radical 2 | = root 10
X-radical 2 = positive and negative root 10
X = root 2 + root 10 or x = root 2 - root 10

Given that the angle between vector a and vector B is 45 degrees, the absolute value of vector a = root 2, the absolute value of vector b = 3, so that the angle between vector B + in vector a and in vector B + vector a is acute angle, and the value range of the obtained value

The angle between vector B + input vector a and input vector B + vector a is an acute angle
(B + in a) * (in B + a) > 0 and (B + in a) and (B + in a) are not collinear
(B + in a) * (in B + a)
=In | B | 2 + in | a ^ 2 + (in ^ 2 + 1) a * B
=11 in + (in ^ 2 + 1) √ 2 * 3 * √ 2 / 2
=3 in ^ 2 + 11 in + 3 > 0
==>In (- 11 + √ 85) / 6
If (B + in a) and (in B + a) are collinear, then in = 1, in = - 1
The value range is
Enter (- 11 + √ 85) / 6 and input ≠ 1