X-y-x is the reciprocal root of x-y-1

X-y-x is the reciprocal root of x-y-1

Because the radical x + Y-3 and the radical x-y-1 are opposite numbers to each other
So x + Y-3 = 0, x-y-1 = 0 (because the root is greater than or equal to 0)
x+y=3 x-y=1
The sum is 2x = 4, x = 2
Y = 1
(x-y)^2009=1^2009=1
The square root of 1 is plus or minus 1

The square of (x-y-1) and 5x-3y-1 under the root sign are opposite to each other. Find the square root of x square + y square

If one is greater than 0, the other is less than 0. Therefore, x-y-1 = 05x-3y-1 = 0, the solution is x = - 1, y = - 2x? + y? = 5

Given that the cube of the radical 3x-7 and the cube of the radical 3Y + 4 are opposite to each other, then x + y =?

Because: the cube of the radical 3x-7 and the cube of the radical 3Y + 4 are opposite numbers to each other
So: 3x-7 and 3Y + 4 are opposite numbers
So; (3x-7) + (3Y + 4) = 0
3x-7+3y+4=0
3（x+y）-3=0
3（x+y）=3
x+y=1

If the cubic root sign 3x-7 and the cubic root sign 3Y + 4 are opposite numbers, and the root sign m-2 and root 5-m + n are opposite numbers to each other, find the arithmetic square root of (x + y + m + n)

The three times root number 3x-7 and the three times root number 3Y + 4 are opposite numbers

If y= 3x−2+ 2 − 3x + 1, find the square root of 3x + y

It can be concluded from the meaning of the title
3x−2≥0
2−3x≥0 ，
The solution is: x = 2
3，
Then y = 1,
3x+y=2+1=3，
So the square root of 3x + y is ± 3

Under the root sign (3x + 2Y + 6-m) + under the root sign (2x + 3y-m) + under the root sign (x + Y-2) = 0, find the square root of M?

Under root sign (3x + 2Y + 6-m) + under root sign (2x + 3y-m) + under root sign (x + Y-2) = 0
They're all nonnegative
So each equation = 0
3X+2Y+6-m=0①
2X+3Y-m=0②
X+Y-2=0③
Solving equations
① + 2
5x+5y-2m=-6
By substituting x + Y-2 = 0 ③ into the above formula, the
5(x+y)-2m=-6
5*2-2m=-6
2m=16
M=8
The square root of M
=±2√2

If the square roots of 3x-y-1 and 2x + y-4 are opposite to each other, find the arithmetic square root of X + 4Y Square root. Correct

If the square roots of 3x-y-1 and 2x + y-4 are opposite to each other
｜3X-Y-1｜＋√﹙2X+Y-4﹚=0
3x－y－1=0,2x＋y－4=0
The solution is x = 1, y = 2
X+4Y=1＋8=9
The arithmetic square root of X + 4Y is 3

If xym is suitable for the relation √ 3x + 5y-3-m + √ 2x + 3y-m = √ x + y-2009 + Radix 2009-x-y, try to find the arithmetic square root of m-1912

: ∵ x + y-2009 ≥ 0, 2009-x-y ≥ 0 ᙽ x + y = 2009 ① x + y-2009 = 2009-x-y = 0 ﹤ √ (3x + 5y-3-m) + √ (2x + 3y-m) = 0

Xym is suitable for the formula (3x + 5y-3-m) root sign + (2x + 3y-m) root sign = (x + y-2009) root sign + (2009-x-y) to find the arithmetic square root of m-1912

∵x+y-2009≥0 , 2009-x-y≥0
∴x+y=2009 ① x+y-2009=2009-x-y=0
∴√(3x+5y-3-m)+√(2x+3y-m)=0
∴3x+5y-3-m=0②
2x+3y-m=0③
② - 3, x + 2Y = 3 4
④ - 1, y = - 2006
Substituting ①, x = 4015
x. Substituting y into ③, M = 2012
The arithmetic square root of M + 1912 = 2012 + 1912 = 3924 is the root number 3924 = 6 root sign 109

Given that x.y satisfies the root of the relation, 3x-5y and the absolute value of x-3y + 3 = 0, find the square root of 2x-2 / 3Y

Because both radical and absolute values are > = 0
3x-5y=0,
x-3y+3=0
y=9/4,x=15/4
2x-2/3y=30/4-3/2=6
The square root is root 6, and - root 6