(Radix 12-radix 3) 2007 times * (Radix 2 + Radix 3) 2006 times

(Radix 12-radix 3) 2007 times * (Radix 2 + Radix 3) 2006 times

Is root 12 root 2?
Yes:
(√2-√3)^2007*(√2+√3)^2006
=(√2-√3)^2006*(√2+√3)^2006*(√2-√3）
=（2-3）^2006*(√2-√3)
=√2-√3

(root 3 + 2) 2007 times × (2-radical 3) 2008 times =?

(√ 3 + 2) 2007 times × (2 - √ 3) 2008 times
=[(√ 3 + 2) × (2 - √ 3)] 2007 times × (2 - √ 3)
=(2? (√ 3) 2) 2007 times × (2 - √ 3)
=2007 times of 1 × (2 - √ 3)
=2-√3

(root 3 minus 2) times 2007 times (root 3 plus 2) 2008 times (root 3 minus 2) square multiplication (5 plus 2 roots 6) plus 1

(2) the root of (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) (+ (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2)

If the square of root (2a-1) is 1-2a, then () A. A = half

Select B.A

If the square of the root sign (2a-3) is 3-2a, then the value range of a is?

The square of root (2a-3)
=|2a-3|=3-2a
In other words, | 2a-3 | = - (2a-3)
So 2a-3 ≤ 0
a≤3/2

Given the square of a-2a-b = - A, B < 0, find the value of a: B

The square of a under radical - 2a-b = - A
a²-2a-b=a²
-2a-b=0
2a=-b
a:b=-1/2

What is the number of (- 1 / 2) to the power of 2006 + (- 1 / 2) to the power of 2007?

(- 1 / 2) to the power of 2007 = the power of - 1 / 2 * (- 1 / 2) to the power of 2006
It is obtained by adding the law of distribution
(- 1 / 2) to the power of 2006 + (- 1 / 2) to the power of 2007
=2006 power of (1 + - 1 / 2) * (- 1 / 2)
=The power of 2006 of 1 / 2 * (- 1 / 2)
=The power of 2006 of 1 / 2 * (1 / 2)
=(1 / 2) to the power of 2007
Ah, it's a little bit messy. Do you understand

What is the - 2006 power of (- 0.25) times the 2007 power of 4?

(-0.25)^-2006×4^2007
=(-4)^2006×4^2007
=4^2006×4^2007
=4^4013

What is the power of (- 2) in 2006 and the power of (- 2) in 2007?

(-2)^(2006)+(-2)^2007
=2^2006-2^2007
=2^2006-2×2^2006
=-2^2006

Compare the 2007 power of 2006 and the 2006 power of 2007

Let a ln [b ^ A] / ab
So ln [a ^ b] > ln [b ^ A]
So a ^ b > b ^ a
So 2006 ^ 2007 > 2007 ^ 2006
2006^2007=6.0003125040142080954278532323428e+6627
2007^2006=8.1288518757786114101739720917895e+6624