If the root sign 3x + 1 is a quadratic radical, then the value range of X is that this is all my wealth Given that the two sides of a triangle are 1.3 and the third side length is the root of the equation x2-5x + 6 = 0, then the perimeter of the triangle The result of root number 12 - root 3 is If x is a real number, then the following formula must be meaningful: a root x B radical x + 1 C x + 1 / 1 D. x 1 / 1

If the root sign 3x + 1 is a quadratic radical, then the value range of X is that this is all my wealth Given that the two sides of a triangle are 1.3 and the third side length is the root of the equation x2-5x + 6 = 0, then the perimeter of the triangle The result of root number 12 - root 3 is If x is a real number, then the following formula must be meaningful: a root x B radical x + 1 C x + 1 / 1 D. x 1 / 1

1. Given that the two sides of a triangle are 1.3 and the third side length is the root of the equation x2-5x + 6 = 0, then the perimeter of the triangle
X? - 5x + 6 = 0, (x-3) × (X-2) = 0, x = 2 or 3. When x = 2, the triangle cannot be formed, so when x = 3, the circumference is 7
2. The result of calculating root number 12 - root 3 = 2 times root 3 - root 3 = root 3
3. If x is a real number, then the following formula must be meaningful: a radical x B radical x + 1C x + 1 / 1 D. x 1 / 1
At the beginning of the question, the writing is too ugly. What is there under the radical?

Quadratic root: 1. To make the following formula meaningful, find the value range of X: ① √ 3x + 6 ② √ 5-x (because ∵ so ᙽ so ᙽ, √ is the root sign.) 2. Write the value range of the independent variable X of the following functions: ① y = √ 9-x ② y = √ 4x ③ y = √ 8 + 2x ④ y = √ 4x + 3, ⑤ y = √ - 2x

1. To make the following formula meaningful, find the value range of X: ① 3x + 6 ② √ 5-x
① In order to make √ (3x + 6) meaningful, 3x + 6 must be ≥ 0, and the solution is: X ≥ - 2
② In order to make √ (5-x) meaningful, 5-x must be ≥ 0, and the solution is: X ≤ 5
2、①X≤9,
②X≥0
③X≥-4,
④X≥-3/4,
⑤X≤0.

If the result of the reduction of the absolute value of the square of the subradical (x-1) + X-2 is 2x-3, what is the value range of X Please answer me in 20 minutes. Quick

X is greater than or equal to 2,

Under the root sign (x-4) plus (x + 4) + 3 is greater than y, and the absolute value X-Y - absolute value Y-5 is simplified

∵ X-4 ≥0；X+4 ≥0 ∴X=4 ∴Y

Given 2 < x < 5, simplify the square of root sign (X-2) + the square of (X-5)

The square of root (X-2) + the square of (X-5)
=x-2-x+5
=3
The first floor is obviously wrong

If 2 ＜ x ＜ 3, simplify: the square of (X-2) + x-3 is equal to?

The square of (X-2) + x-3
=│x-2│+│x-3│
=x-2+3-x
=1

When x is known to be greater than or equal to 0, the square of | 1-x | - radical x is reduced

|The square of 1-x | - radical x = | 1-x | - | x|
When x is greater than or equal to 0 and less than or equal to 1: the original formula = 1-x-x = 1-2x
When x is greater than 1: the original formula = x-1-x = - 1

Given the radix 2x-6, it is meaningful to simplify | X-1 | - | 3-x| As the title

Greater than or equal to 0 under root sign
So 2x-6 > = 0
x>=3
x> = 3, so x > 1, so | X-1 | = X-1
x> = 3, so 3-x

The radical 2x-6 is meaningful and simplified: radical (x-1) - radical (3-x) ^ 2

The radical 2x-6 is meaningful, so 2x-6 ≥ 0, X ≥ 3
So X-1 > 0, 3-x ≤ 0
So root sign (x-1) ^ 2-radical sign (3-x) ^ 2 = x-1-x + 3 = 2
Note: the first root should also have a square

If the result of the reduction of the absolute value i1-xi-the square of root x-8x + 16 is 2x-5, then the range of X is

I1-xi-the second power of radical x-8x + 16
=|1-x | - radical (x-4) ^ 2
=|1-x|-|x-4|=2x-5=(x-1)+(x-4)
So: | 1-x | = X-1, | x-4 | = - (x-4)
So x = 0
X-4