If x, y are real numbers and | x + 2|+ If Y-3 = 0, then the value of (x + y) 2010 is___ .

If x, y are real numbers and | x + 2|+ If Y-3 = 0, then the value of (x + y) 2010 is___ .

According to the meaning of the title, x + 2 = 0, Y-3 = 0,
X = - 2, y = 3;
So (x + y) 2010 = 1
So the answer is: 1

If x and y are real numbers and the absolute value of X + 2 + root Y-3 = 0, then the value of (x + y) 2010 is?

x+2=0
x=-2
y-3=0
Y=3
(x+y)^2010=1

If x and y are real numbers, and the absolute value of (x + 1) plus (root y minus one) equals 0, then the value of (Y / x) to the power of 2011 is?

Because | x + 1 | ≥ 0, and the root sign (Y-1) ≥ 0, and | x + 1 | + root (Y-1) = 0
So x = - 1, y = 1
So (Y / x) ^ 2011 = - 1

If | x + the quadratic power of 3 | + (y + (3 under root) / 3) = 0, then what is the 2005 power of (XY)

That is, x + √ 3 = 0, y + √ 3 / 3 = 0
So x = - √ 3, y = - √ 3 / 3
So xy = 1
So the 2005 power of the original formula = 1 = 1

If x = radical 2-radical 3, y = radical 2 + Radix 3, then x is 2005 power × y is 2006 power=

∵x=√2-√3
y=√2＋√3
∴xy=（√2-√3）（√2＋√3）=-1
x^2005·y^2006
=（xy）^2005·y
=（-1）^2005 ×（√2＋√3）
=-√2-√3

If x = root 2-root 3, y = root 2 + root 3, then what is the 2005 power of x times the 2006 power of Y I'm looking for people with high intelligence quotient, right

xy=(√2-√3)(√2+√3)=(√2)²-(√3)²=2-3=-1
So the original formula = x ^ 2005 * y ^ 2005 * y = (XY) ^ 2005 * y = - 1 * y = - √ 2 - √ 3

The absolute value of the third power of (minus 1) plus the zero power of (2009 minus root 2) minus (1 / 2) is equal to?

The power 0 of a non-zero number is equal to 1

What is the 2009 power of root 3 minus the 2009 power of root 2?

The answer is definitely not 1
Because the square of √ 3 minus the square of 2 equals 1
Moreover, the x power of √ 3 is an increasing function, the x power of √ 2 also makes the increasing function, and the growth rate of X of √ 3 is greater than that of √ 2, so the answer to the question must be greater than one, and it is a large number. I think there should be no simple algorithm

(1) The quadratic power of B + 3 + (c-2009) of the absolute value of A-2 + given (2) Known: root X-1 + radical 1-x = y + 4, find the value of XY 91) the square of A-2 + | B + 3 | + (c + 2009) under known radical sign

I don't understand what you are writing
The second problem is that X-1 ≥ 0, 1-x ≥ 0, so x = 1 and y-4 = 0, so y = 4
xy=4

The power of 2009 of (root 3 - root 2) x 2010 power of (root 3 + root 2)

(√3-√2)^2009×(√3+√2)^2010=(√3-√2)^2009×(√3+√2)^2009×(√3+√2)=[(√3-√2)(√3+√2)]^2009×(√3+√2)=[(√3)²-(√2)²]^2009×(√3+√2)=(3-2)^2009×(√3+√2)=1^2009×(√3+√2)=1×(√3+...