What's the difference between electric work and electric power?

What's the difference between electric work and electric power?

Corona, electric power refers to the electric work per unit time, that is, electric power = electric work / time
Electric power is the number of electric work per unit time. The specific formula is electric power P = electric work w / working time t
The area of equilateral triangle with known side length a is √ 3 / 4A ^ 2, and the side length is 6 √ 3
It is known that the area of equilateral triangle with side length a is √ 3 / 4 · a ^ 2, and the perimeter and area of equilateral triangle with side length 6 √ 3cm are calculated
That is, a = 6 √ 3
Then perimeter = 3A = 18 √ 3cm
Area = √ 3 / 4 * (6 √ 3) & sup2;
=√3/4*36*3
=27√3cm²
1. It is known that the length of one side of the triangle is √ 32cm, and the height of this side is √ 12cm. Find the 2 of the triangle. Because the equilateral triangles are similar, the perimeter C = 3 * 5 √ 3 = 15 √ 3 (CM) area s = √
It is proved by mathematical induction that x ^ (2n + 1) + y ^ (2n + 1) can be divided by X + y
Urgent! Homework tonight
Can you do it step by step? I'm sorry for my stupidity. I can't understand what you said upstairs. From [suppose n = k when the proposition holds, when n = K + 1 prove the proposition holds
When n = 0, it must be true. Now when n-1, the conclusion is true. Look at the case of N; X ^ (2n + 1) + y ^ (2n + 1) = x ^ (2n + 1) + x ^ (2n) * y + XY ^ (2n) + y ^ (2n) + y-xy ^ (2n) = (x ^ (2n) + y ^ (2n)) (x + y) - (x ^ (2n-1) + y ^ (2n-1)) the second half of the XY equation (x ^ (2n-1) + y ^ (2n-1)) XY according to the induction
x^(2n+1)+y^(2n+1)
=(x+y)^(2n+1)
So it's divisible by X + y
x^(2n+1)+y^(2n+1)
=(x+y)(2n+1)
So it's divisible by X + y
What is the difference between electric power and electric work?
Such as the title
The unit of electric power is watt (W), and the unit of electric work is Joule (J)
Electrical power is the electrical work done per unit time
As shown in the figure, parabola y = - x ^ 2 + 2x + 3 ~ let the area of triangle BCF be s, and find the functional relationship between S and m
As shown in the figure, the parabola y = - x 2 + BX + C intersects the X axis at two points a (1,0) and B (- 3,0)
(1) The analytical formula of the parabola is obtained;
(2) Let the parabola in (1) intersect the y-axis at point C. is there a point Q on the symmetry axis of the parabola, so that the perimeter of △ QAC is the smallest? If so, find out the coordinates of point Q; if not, explain the reason;
(3) Is there a point P in the second quadrant of the parabola in (1) to maximize the area of △ PBC? If so, calculate the coordinates of point P and the maximum area of △ PBC. If not, explain the reason
1,y=-x²-2x+3
2, exist, connect CB, the symmetry axis of the intersecting parabola is at the Q point, Q point is the solution. You can choose any other point Q ', there must be CQ ′ + BQ ′ = CQ ′ + AQ ′ > CB = CQ + QA
Get Q (- 1,2 √ 2)
3. There is a point p; since BC is definite, in order to maximize the area, that is, to find the maximum height, it is obvious that when BC is tangent to the parabola, h can take the maximum value
If the solution is tangent to the parabola x + sup + 2, then there is only one solution,
B = 21 / 4, x = - 3 / 2, y = 15 / 4, combined with the image, the distance between the line and BC is √ 2 / 2B = 21 / 8 √ 2
The maximum area of triangular PBC is 63 / 8
It is proved by mathematical induction that x ^ 2n - 1 can be divided by X + 1,
Let n = k, x ^ 2N-1 be divisible by X + 1. Let x ^ 2k-1 = (x + 1) [f (x) - 1] (where f (x) is an integer), x ^ 2K = (x + 1) [f (x) - 1] + 1, then when n = K + 1, x ^ 2 (K + 1) - 1 = x ^ 2K * x ^ 2-1 = ((x + 1) [f (x) - 1] + 1
The verification is true when n = 1.
Suppose that x ^ 2K - 1 is divisible by X + 1 when n = K
So for n = K + 1
(x ^ 2K - 1) times x ^ 2 is divisible by X + 1.
That is, x ^ 2 (n + 1) - x ^ 2 can be divided by X + 1. If a number is divisible by X + 1, then the sum of this number plus a number divisible by X + 1 can also be divisible by X + 1.
That is x ^ 2 (n + 1) - x ^ 2 + (x-1) (x +... Expansion
The verification is true when n = 1.
Suppose that x ^ 2K - 1 is divisible by X + 1 when n = K
So for n = K + 1
(x ^ 2K - 1) times x ^ 2 is divisible by X + 1.
That is, x ^ 2 (n + 1) - x ^ 2 can be divided by X + 1. If a number is divisible by X + 1, then the sum of this number plus a number divisible by X + 1 can also be divisible by X + 1.
That is, x ^ 2 (n + 1) - x ^ 2 + (x-1) (x + 1) can also be divided by X + 1
So x ^ 2 (n + 1) - 1 can also be divided by X + 1.
Get the certificate ~ put it away
What is the difference between electric work and electric power
The work done by current is called electric work, which has no physical quantity to express. Electric power P is used to express the speed of electric energy consumed by electrical appliances. We can also understand the relationship between the two. The amount of work done by current (electric work) will consume electric energy w (commonly known as electricity consumption), and the amount of electric energy consumed per unit time (such as one second) is electric power, Take your time. You should understand
It is known that the side length of an equilateral triangle is 2x. The area s of the triangle is expressed as a function of X, and the sketch of the image is drawn
It is known that the side length of an equilateral triangle is 2x. The area s of the triangle is expressed as a function of X, and the sketch of the image is drawn
S=(1/2)×sin60°×2x×2x=(1/2)×(√3/2)×2x×2x=√3x²;
The graph is that the vertex is at the origin, the opening is upward, take the special points (1, √ 3), (- 1, √ 3) and you can roughly draw it
It is proved that the inequality nlnn ≥ (n-1) ln (n + 1) holds for any positive integer n
Let f (n) = lnn / (n-1) f '(n) = (n-1-nlnn) / (n (n-1) ^ 2) Let G (n) = n-1-nlnn G' (n) = - lnn, because n > = 1, so lnn > = 0, G '(n) = 1, so f' '(n) > = 0
Is electric power related to time
For example, if the electric power is 150KW, does this 150KW refer to the work in one second or within one hour? If it is converted into power consumption, how can it be converted? Is 150KW * 1kW / h = 150 kwh? Will two different units be multiplied and neutralized? For example, is kW * kW / h = kW / h? Why?
Degree is kW / hour. How can 150KW * 1kW / hour be equal to 150KW / hour? How is this unit changed?
I'm talking about "150KW * 1kwh" = 150KW / h. "I asked 150KW multiplied by 1kW / h. isn't there two kW here? Doesn't it take square to multiply two kW? The result is 150KW / h. why isn't it 150kw2 / h
Power has nothing to do with time. Power is a physical quantity that represents the speed of doing work. The relationship between power and work is just like the relationship between speed and displacement. Generally speaking, "degree" is used to measure the amount of work done by electric energy (any kind of energy can be expressed in joules). In terms of electric energy, the commonly used power is w and kW. If the electric appliance is marked with kW power, the power of the electric appliance is w, Explain the work done by this appliance in an hour. Work = power * time, the unit of degree is kilowatt (Times) hour, not division. Degree = kW · H = 1000W · 3600s = 3.6 * 10 ^ 6 Joule · s