150 kW motor is 100 meters away from transformer, is it safe to use 70 square copper cable The voltage is 380V, how much is the voltage drop

150 kW motor is 100 meters away from transformer, is it safe to use 70 square copper cable The voltage is 380V, how much is the voltage drop

1. 3. Resistance: 0.022 * 100 / 120 = 0.018 ohm. 4. Voltage drop: 0.018 * 228 = 4.18v5. Loss: 0.018 * 228 * 228 = 935w (net resistance loss)
Can the absolute value of a number be negative? What number's absolute value is negative?
As above
Impossible. The absolute value of positive and negative numbers is positive, and the absolute value of 0 is 0
The absolute value of a value cannot be negative, it can only be an integer or zero
The absolute value of a number is the distance from the number to the origin on the real axis, while the imaginary number I ^ 2 = - 1 under the root sign (I ^ 2) = | I|
How can these three words be negative? It can only be an integer and the minimum is 0
Impossible. The minimum is zero
Three phase four wire one kilowatt is equal to how many ampere current
Three phase four wire parallel case, thank you!
9 A / piece = 1
Power (kw) / voltage (kV) / piece 3 = current (a)
How much square wire do two 5.5kW motors (wiring distance is 120m) need to be connected? (copper? Aluminum?)
It is recommended to use 16 square aluminum wire. If the power supply is 380V, it is 375v when passing through 120m 16 square aluminum wire to the motor
It is proved by mathematical induction that 49 ^ n + 16n-1 can be divided by 64
Such as the title
Wait until 12 o'clock tomorrow~
When n = 1, 49 ^ n + 16N - 1 = 49 + 16 - 1 = 49 can be divided by 64
Let 49 ^ k + 16k-1 be divisible by 64, then
49^(k+1)+16(k+1)-1
=49*49^k+16k+15
=49*(49^k+16k-1)+64*(-12k+1)
Therefore, 49 ^ (K + 1) + 16 (K + 1) - 1 can be divisible by 64
According to mathematical induction, 49 ^ n + 16N - 1 can be divided by 64 for any nonnegative integer n
It is proved that: (1) when n = 1, 49 + 16-1 = 64 can be divisible by 64. (2) suppose that when n = k, 49'k + 16k-1 = 64M, thus 49'k = 64m-16m + 1,49 '(K + 1) + 16 (K + 1) - 1 = 64 (49m-12k + 1)
How much current is a kilowatt
If the power factor is not considered, i.e. the power factor is 1,
For 220 V single-phase system, 1kW is 4.55 a current;
For 380V three-phase system, 1kW is the current of 1.52a;
For 6000V three-phase system, 1kW is the current of 0.096a;
For 10000v three-phase system, 1kW is the current of 0.058a;
For 35000v three-phase system, 1kW is the current of 0.016a;
The voltage of three-phase system is 6600.0081 kW;
For 110000V three-phase system, 1kW is the current of 0.0052a;
For 220000v three-phase system, 1kW is the current of 0.0026a;
For 500000v three-phase system, 1kW is the current of 0.0012a;
For 750000v three-phase system, 1kW is the current of 0.0007a;
For 1000000v three-phase system, 1kW is the current of 0.0005a;
At present, there are only the first 10 voltage levels in China, and the last 1000kV voltage level is under preparation. You can choose which one you want
What does power cable 5 (3 * 240 + 1 * 120) mean
Hello
Power cable 5 (3 * 240 + 1 * 120) means: five power cables, each of which is three-phase 240 & # 178; plus neutral wire 120 & # 178; (four core cable). That is, five cables should be used as one. Phase core 5 * 240 = 1200 & # 178; neutral wire 5 * 120 = 600 square
If n is a natural number within 100, how many n can divide 2N-1 by 7?
A.32 B.33 C.34 D.35
N is a natural number within 100, 0 ≤ n ≤ 100-1 ≤ 2n - 1 ≤ 199, so 2n - 1 is an odd number from - 1 to 199. Because in - 1 to 199, one of every 14 numbers is an odd or even number divisible by 7. Therefore, there are a total of [199 - (- 1) + 1] △ 14 = 14.36, rounding down, and there are 14
0*2 - 1 = -1
100*2 - 1 = 199
From - 1 to 199, the odd numbers divisible by 7 are:
199 ÷ 7 = 28
28 / 2 = 14
How much current is a kilowatt
The question is just like I asked you "how many kilos is a meter". Kilowatt is the unit of power. Power and current are not the same physical quantity. How can there be a conversion relationship? It can only be said that when the voltage is known, the current can be calculated according to P = UI, i.e. I = P / u
Insulation resistance standard of vv22 3 * 6mm2 0.6/1kv power cable?
Do you mean resistance standard or executive standard? If executive standard, it is GB / t12706.1-2008