The square of 5 + 3x + X to solve the equation

The square of 5 + 3x + X to solve the equation

3x²+x+5=0
Δ=1-80=-79
Use that what, 2A - B plus minus root sign b square + 4ac
(5+3x)2+x=0
9x2+31x+25=0
∵a=9，b=31，c=25
∴b2-4ac=961-900=61〉0
∴x=（-13±√61）÷36
∴x=（-13+√61）÷36，x=（-13-√61）÷36
I think so. Your topic is not very clear
3x²+x+5=0
Δ=1-80=-79
Proof: the product of four consecutive integers plus 1 is the square of an integer
Let the four consecutive integers be n-1, N, N + 1, N + 2, then (n-1) n (n + 1) (n + 2) + 1, = [(n-1) (n + 2)] [n (n + 1)] + 1 = (N2 + n-2) (N2 + n) + 1 = (N2 + n) 2-2 (N2 + n) + 1 = (N2 + n-1) 2. Therefore, the product of four consecutive integers plus 1 is the square of an integer
4X & # 179; (- Y & # 179;) & # 178; - 3x · (- x) & # 178; · (- Y & # 178;) & # 179;, where x = - 1, y = 2,
4x³（-y³）²-3x·（-x）²·（-y²）³
=-4x³y^6+3x³y^6
=-x³y^6
=-(-1)³2^6
=64
The complete square formula of mathematics in grade two
Question 1: the result of calculating (a + b) (- a-b) is () (direct answer)
A.a²-b²
B.-a²-b²
C.a²-2ab+b²
D.-a²-2ab+b²
Question 2: if X & # 178; - kxy + 9y & # 178; is a complete square, then the value of K is () (direct answer)
A.3
B.6
C.±6
D.±81
Question 3: calculation (direct answer)
（-x-y）²=__________
(-2a+5b)²=__________
x²+y²=(x+y)²_______ =(x-y)²+_______
Fourth question:
①（-xy+5）²=
②（x+3)（x-3)(x²-9）=
The first question: the result of calculating (a + b) (- a-b) is (d) (direct answer) A.A & # 178; - B & # 178; B. - A & # 178; - B & # 178; C.A & # 178; - 2Ab + B & # 178; D. - a & # 178; - 2Ab - B & # 178; the second question: if X & # 178; - kxy + 9y & # 178; is a complete square, then the value of K is (C
B
C
x2+y2+2xy
4a2+25b2+20ab
-2xy 2xy
x2y2+25+10xy
（x2-9）2
1、B,2、B
3、-X²-2XY＋Y²
-4A²＋20AB-25B²
-2XY ＋2XY
4、①-X²Y²﹢10XY﹢25
②=﹙X²-3²﹚﹙X²－3²﹚=﹙X²－9﹚²
How to solve the equation of 0.36 + 5-3 / 4x = 3 / 5?
0.36+5-3/4x=3/5
0.36+5-0.75x+0.75x=3/5+0.75x
0.75x+0.6-0.6=5.36-0.6
0.75x/0.75=4.76/0.75
x=4.76/0.75
0.36+5-3/5=3/4x
4.76=0.75X
X=4.76/0.75
0.36+5-3/5=3/4x
4.76=0.75X
X=4.76/0.75
[(2m+n) (2m-n)]^2
[(2m+n) (2m-n)]^2
= （4m² - n ²）²
= （4m ²）² - 8m²n² + （n²）²
=16m quartic - 8m & sup2; n & sup2; + n quartic
[(2m+n) (2m-n)]^2
=（4m^2-n^2)^2
=16m^4-8m^2n^2+n^4
1. 4x-3 / 5 = 5 solution equation
4x-3/5=5
4x=5+3/5
4x=28/5
x=(28/5)/4
x=7/5
(2x-y)²-4(x-y)(x+2y)
Please tell me the process and how to calculate it
2x²+y²+(4x+4y)x+2y
=2x²+y²+4x²+6xy+4xy+6y²
=2x²+4x²+4x²+y²+6y²+6xy
=10x²+7y²+6xy
I know it's wrong to do this. What's wrong? Help me to analyze it!
(2x-y)²-4(x-y)(x+2y)
=4x²-4xy+y²-4(x²+xy-2y²)
=4x²-4xy+y²-4x²-4xy+8y²
=9y²-8xy
If you don't understand this question, you can ask,
(2x-y)²-4(x-y)(x+2y)
=4x^2-4xy+y^2-4x^2-8xy+4xy+4y^2
=5y^2-8xy
(2x-y)²-4(x-y)(x+2y)
=4x²-4xy+y²-4(x²+xy-2y²)
=4x²-4xy+y²-4x²-4xy+8y²
=9y²-8xy
This topic can be divided into two steps. One is before minus sign and the other is after minus sign
Generally, the coefficient is calculated at last
When you calculate 2x & # 178; + Y & # 178; + (4x + 4Y) x + 2Y, (4x + 4Y) is not multiplied by 2Y
The correct process is as follows: (2x-y) & # - 4 (X-Y) (x + 2Y)
=4x²-4xy+y²-4(x²+xy-2y²)
=4x²-4xy+y²-4x²-4xy+8y²
... unfold
The correct process is as follows: (2x-y) & # - 4 (X-Y) (x + 2Y)
=4x²-4xy+y²-4(x²+xy-2y²)
=4x²-4xy+y²-4x²-4xy+8y²
=9y²-8xy
Error: 1. Careless, write the original question - 4 as + 4 (x + 2Y)
2、 Wrong understanding. Multiply (x + 2Y) and later to (4x + 4Y) x + 2Y
3、 Wrong formula, (2x-y) &# 178; =?? 2x²+y²
This problem mainly uses the basic knowledge of formula and polynomial multiplication,
I'm very happy to answer for you. I hope my answer will help you ~ ~ I don't understand, you can ask!
If you have solved your problem, please put it away in time
A: the first step was wrong. The square of (2x & nbsp; - & nbsp; y) is solved by the complete square formula, that is 4x2 & nbsp; - 4xy + Y2. Using cross multiplication to solve - & nbsp; 4 (X & nbsp; - & nbsp; y) (x + 2Y), namely & nbsp; - & nbsp; 4x2 & nbsp; - & nbsp; 4xy + 8y2 & nbsp;. The last is to merge the similar items: 9y2 & nbsp; - & nbsp; 8xy.
3/4*(X-10)=4X/5-30+10
3/4(x-10)=4x/5-20
Take 20 on both sides
15x-150=16x-400
16x-15x=400-150
x=250
871*120/60
=871*（120/60）
=871*2
=1742
2 times 1 / 2 = (2 times 1 / 2) 3 = (1)
2-y/2x+2y-x²+y²/x²-y²
(X-Y) (X-Y) (as (X-Y) (X-Y) / 2 (X-Y) (2 (X-Y) / 2 (x + y) [(X-Y) / 2 (X-Y) / 2 (X-Y) / 2 (X-Y) / 2 (x + y) [(X-Y) \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\) / [2 (x + y) (X-Y)] = - (x + y) &