Solve equation 5 (X-2) + 3x = 14.; -) answer if you have a task

Solve equation 5 (X-2) + 3x = 14.; -) answer if you have a task

5（x-2）+3x=14
5x-10+3x=14
8x=24
X=3
Given 3x-6y-5 = 4, find the value of 2x-4y + 2011
3x-6y-5=4
3x-6y=4+5
3(x-2y)=9
x-2y=3
So: 2x-4y + 2011 = 2 (x-2y) + 2011 = 2x3 + 2011 = 2017
3x-6y=9
x-2y=3
2x-4y=6
So 2x-4y + 2011 = 6 + 2011 = 2017
If 3x-6y-5 = 4, then 3x-6y = 9, that is, x-2y = 3
2x-4y+2011=2(x-2y)+2011=2*3+2011=2017
(100-3x) △ 4 = 14.5
(100-3x)÷4=14.5
100-3x=14.5×4
100-3x=58
3x=100-58
3x=42
x=42÷3
x=14
How to solve the equation of (4x-20) divided by (3x-20) = two thirds? I'm in a hurry
(4x-20) divided by (3x-20) = two thirds
(4x-20) = (3x-20) × two thirds
3(4x-20)=2(3x-20)
12x-60=6x-40
6x=20
x=10/3
Solving equation 3x + 13 / 9 = 14 / 9
3x + 13/9 = 14/9
3x = 14/9-13/9
3x = 1/9
x = 1/27
D7gbbdhn sending vlds
3X=14/9-13/9=1/9
X=1/27
3x+13/9=14/9。
3x=14/9-13/9.
3x=1/9.
x=1/27.
3x+9/13=9/14
3x=9/14-9/13
3x=-9/1
x=-27/1
3X=14/9-13/9=1/9
X = 1 / 9 divided by 3 = 1 / 27
3x = 14 / 9-13 / 9
3X=1/9
X=1/27
Solution equation: 4x-1 = 3x-1. Xiao Li's solution is as follows: if you add 1 to both sides of the equation, you get 4x = 3x. If you divide X by both sides of the equation, you get 4 = 3?
Can you point out where Xiao Li is wrong?
Divide both sides by X. This is not correct
When x = 0, X cannot be a divisor
If you add 1 to both sides of the correct equation, you get 4x = 3x,
Subtract 3x from both sides of the equation to get x = 0
When x = 0, both sides cannot be divided by X at the same time
The solution of this equation is x = 0
It is OK to divide the two sides of the equation by a number that is not equal to zero.
But the above equation is true if x = 0
Should be shifted: 4x-3x = 0, x = 0
Divide both sides of the equation by X
In the case of not sure if x is zero
You can't divide by X
If x = 0, the equation is meaningless
Xiao Li is wrong!
If both sides of the equation multiply or divide by a number that is not zero, the equation still holds. However, dividing both sides of the equation by an X at the same time does not guarantee that x ≠ 0, and the solution of this equation is x = 0, so her result is absurd.
The equation is wrong.
7 / 3x - 9 / 14 = 9 / 13 - 2 / 3x to solve the equation
3x out of 7-14 out of 9 = 3x out of 9-3X out of 2
3x of 7 + 3x of 2 = 14 of 9 + 13 of 9
6X of 14 + 21x of 14 = 27 of 9
27x of 14 = 27 of 9
X = 14 / 9
3x／7+3x/2＝13／9+14/9
27x／14＝3
x＝14/9
The solution is 3x out of 7-14 out of 9 = 13 out of 9-3X out of 2
That is, 3 / 7x-14 / 9 = 13 / 9-3X / 2
That is, 3 / 7X + 3x / 2 = 13 / 9 + 14 / 9
That is, 6 / 14x + 21x / 14 = 27 / 9
That is 27x / 14 = 27 / 9
That is, X / 14 = 1 / 9
That is, x = 14 / 9
7 / 3x-9 / 14 = 9 / 13-2 / 3x, solve the equation 7 / 3x + 2 / 3x = 9 / 14 + 9 / 13
14/6x+14/21x=9/27
14/27x=9/27
... unfold
7 / 3x-9 / 14 = 9 / 13-2 / 3x, solve the equation 7 / 3x + 2 / 3x = 9 / 14 + 9 / 13
14/6x+14/21x=9/27
14/27x=9/27
x=9/27*27/14
X = 9 / 14 "Stow
Try to prove that x (x + 1) (x + 2) (x + 3) + 1 is a complete square formula
Simplifying and decomposing factors
X（X+1）（X+2）（X+3）+1
=(x^2+x)(x^2+5x+6)+1
=x^4+6x^3+11x^2+1
=(x+3x+1)^2
So x (x + 1) (x + 2) (x + 3) + 1 is a complete square formula
X（X+1）（X+2）（X+3）+1
=(x^2+x)(x^2+5x+6)+1
=x^4+6x^3+11x^2+6x+1
=x^4+(3x)^2+1+6x^3+2x^2+6x
=(x^2+3x+1)^2
So x (x + 1) (x + 2) (x + 3) + 1 is a complete square formula
3x-13 / 9 = 14 / 9 x + (3 / 4-3 / 8) = 7 / 8 to solve the equation
3x-13/9=14/9
3x=13/9+14/9
3x=3
x=3÷3
X=1
x+(3/4-3/8)=7/8
x=7/8+3/8-3/4
x=5/4-3/4
x=1/2
It is proved that (X-2) (x-3) (x-4) (X-5) + 1 is a complete square formula
(x-2)(x-3)(x-4)(x-5)+1
=(x-2)(x-5)(x-3)(x-4)+1
=(x^2-7x+10)(x^2-7x+12)+1
=(x^2-7x)^2+22(x^2-7x)+121
=(x^2-7x)^2+22(x^2-7x)+11^2
=[(x^2-7x)+11]^2
=(xsquare - 7x + 10) (xsquare - 7x + 12) + 1
Let x square - 7x be a
(a+10)(a+12)+1
=A square + 22a + 121
=(a + 11) square
[(x-2)(x-5)][(x-3)(x-4)]+1
=(x^2-7x+10)(x^2-7x+12)+1
=(x^2-7x)^2 +22*(x^2-7x) +120+1
=(x^2-7x+11)^2
(x-2)(x-3)(x-4)(x-5)+1
=[(x-2)(x-5)][(x-3)(x-4)]+1
=[x^2-7x+10][x^2-7x+12]+1
=(x^2-7x)^2+22(x^2-7x)+120+1
=(x^2-7x)^2+22(x^2-7x)+121
=(x^2-7x+11)^2
It's a perfect square