Factorization factor: 2x square + xy-y square-4x + 5y-6.3q Factorization factor: 2x square + xy-y square-4x + 5y-6 factorization factor: 1 / 4-N square + m square-m if the side lengths a, B and C of a triangle are integers and a + BC + B + Ca = 4, then the perimeter of the triangle is

Factorization factor: 2x square + xy-y square-4x + 5y-6.3q Factorization factor: 2x square + xy-y square-4x + 5y-6 factorization factor: 1 / 4-N square + m square-m if the side lengths a, B and C of a triangle are integers and a + BC + B + Ca = 4, then the perimeter of the triangle is

1. In this paper, we use the cross phase multiplication method to take y as a constant and arrange X in descending order. The original formula is 2x2 + (y-4) x + (- Y2 + 5y-6) = 2x2 + (y-4) x + [- (y2-5y + 6)] = 2x2 + (y-4) x + [- (Y-2) (Y-3)] 2, 1 / 4-N ^ 2 + m ^ 2-m = (m ^ 2-m + 1 / 4) - n ^ 2 = (m-1 / 2) ^ 2-N ^ 2 = (M + n-1 / 2) 3, a + BC
2X^2+xy-Y^2-4x+5Y-6=(2x-Y+2)(x+y-3)。 (1 / 4) - n ^ 2 + m ^ 2-m = [M - (1 / 2)] ^ 2-N ^ 2 = [M - (1 / 2) - n] * [M - (1 / 2) + n] a + BC + B + AC = 4, a * (1 + C) + b * (1 + C) = 4 (1 + C) * (a + b) = 4, 4 = 1 * 4 = 2 * 2 = 4 * 1, 1 + C = 2, a + B = 2, perimeter = a + B + C = 2 + 1 = 3
Decomposition factor (1) 2x square + xy-y square - 4x + 5y-6 (2) a square - 4AB + 4B square - 6A + 12b + 9
Square factorization of 4x + 12xy + 5Y
4X ^ 2 can be decomposed into 2x and 2x multiplication, 5Y ^ 2 can be decomposed into 5Y and Y multiplication
2x 5y
2x y
This is cross multiplication, so the formula can be written as (2x + 5Y) (2x + y)
(2X+5Y)·（2X+Y）
Original formula = (2x + 5Y) * (2x + y)
2x+5y)(2x+y)
4x^2+12xy+5y^2
=(2x+5y)(2x+y)
4X plus 13 is 36.5 solution
4X+13=36.5
4X=36.5-13
4X=23.5
X=5.875
gtuu
2X & sup2; - 2XY + Y & sup2; = 1, Z is the range of X + 2Y
2X & sup2; - 2XY + Y & sup2; = 1 is equivalent to (X-Y) ^ 2 + y ^ 2 = 1
So we can do variable substitution: Sint = X-Y, cost = y
The proposition is transformed into: finding the value of Sint + cost
Sint + cost = (radical 2) * sin (2t + 45 degrees)
The range of Sint + cost is [- radical 2, radical 2]
4x-20 × 0.3 = 8 solution equation 2.5 × 4-4x = 8 solution equation
 
Given x-2y = 3, find 1 / 2x & sup2; - 2XY + 2Y & sup2;
There is another question
Given X & sup2; + Y & sup2; = 20, X & sup2; + xy-2y & sup2; = 2 (x + 2Y), find the value of X + y
1/2x²-2xy+2y²
=1/2x²-xy-xy+2y²
=1/2x(x-2y)-y(x-2y)
=3/2x-3y
=3/2(x-2y)
=9/2
The original formula = (x-2y) (1 / 2x-y) = 1 / 2 (x-2y) (x-2y) = 9 / 2
Solution equation: 3 / 4x + 1 / 4 = 5 / 8
Please do me a favor
3/4x+1/4=5/8
3/4x=5/8-1/4
3/4x=3/8
x=3/8*4/3
x=1/2
X in molecule
3x/4+1/4=5/8
3x/4=5/8-1/4
3x/4=3/8
X=1/2
X is at the denominator
3/4x+1/4=5/8
3/4x=5/8-1/4
3/4x=3/8
X=2
Calculation: (xy-x & sup2;) / (X & sup2; - 2XY + Y & sup2;) / 2Y · X-Y / X & sup2;
The original formula = - x (X-Y) / (X-Y) & sup2 / 2Y × (X-Y) / X & sup2;
=-2xy(x-y)²/[x²(x-y)²]
=-2y/x
Find the law 1 / 1,1 / 2,2 / 3,2 / 4 () () 1 1 / 2 1 / 6 1 / 24 () () solve the equation 3 / 4x + 2.5 times 4 = 20 3 times 8-60% x = 0
3 / 4x + 2.5 times 4 = 20
0.75x=20-2.5*4
x=40/3
3 times 8-60% x = 0
-0.6x=-24
x=40
1/1, 1/2, 2/3, 2/4 (3)/(5)(3)/(6)
1 1/2 1/6 1/24 (1)/(120)
1*1=1
1*2=2
2*3=6
6*4=24
24*5=120
1/1, 1/2, 2/3, 2/4 (3/5)(3/6)(4/7)(4/8)
1 1/2 1/6 1/24(1/120)(1/720)
3 / 4x + 2.5 times 4 = 20
3/4x=20-10
3/4x=10
x=40/3
3 times 8-60% x = 0
-60%x=-24
x=40