4X ^ 4-5x ^ 2Y ^ 2-9y ^ 4 cross multiplication

4X ^ 4-5x ^ 2Y ^ 2-9y ^ 4 cross multiplication

1x² -9y²
4x² 1y²
Original = (X & # 178; + Y & # 178;) (4x & # 178; - 9y & # 178;)
（2x^2+2y^2）*(2x^2-4.5y^2)
Hope to adopt
a+(b+c)=?a-(b+c)=?a+(b-c)=?a-(b-c)=?(8x-5x0-(4x-9y)=?(2x+2y)+(-5x+2y)=?
a+b+c a-b-c a+b-c a-b+c
8x-5x-(4x-9y)= -x+9y
(2x+2y)+(-5x+2y)= -3x+4y
① Simple operation with complete square formula 1.89.8 & sup2; 2.47 & sup2; - 94 * 27 + 27 & sup2; ② X & sup2; - 2x + Y & sup2; + 6y + 10 = 0 for X, y
①【1】89.8² 【2】47²-94*27+27²
· =(90-0.2)^2 =(47-27)^2
=8100-2×90×0.2+0.04 =20^2
=8064.04 =400
②x²-2x+y²+6y+10=0
X^2-2X+1+Y^2+6Y+9=0
(X-1)^2+(Y+3)^2=0
Because the square of a number is greater than or equal to 0
So X-1 and y + 3 must be both zero for the equation to hold
So x = 1, y = - 3
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89.8^2
＝（90－0.2）^2
＝90＾2－2×90×0.2＋0.2^2
＝8100－36＋0.04
＝8064.04
47^2－94×27＋27^2
＝（47－27）^2
＝20^2
＝400
x^2－2x＋y^2＋6y＋10＝0
x^2－2x＋1＋y^2＋6y＋9＝0
Using two different methods to solve the equation: 4 (x-1) + 6 (3-4x) = 7 (4x-3)
4（x-1）+6（3-4x）=7（4x-3）
4x-4+18-24x=28x-21
4x-24x-28x=4-18-21
-48x=-35
x=35/48
4（x-1）+6（3-4x）=7（4x-3）
4(x-1)+6(3-4x)-7(4x-3)=0
4(x-1)+6(3-4x)+7(3-4x)=0
4(x-1)+13(3-4x)=0
4x-4+39-52x=0
48x=35
x=35/48
X & sup2; + 1 + () = () & sup2 forms the complete square formula. Except ± 2x, write another one
Is to add a monomial
1/4X^2
(X+1/2X)^2=X^2+1+1/4X^2
4X + 3 or 3-4x
x²+1+（-1）=（x)²
4X + 3 * 0.7 = 6.5
4x+2.1=6.5
4x=4.4
x=1.1
One point one
4x+2.1=6.5
4x=4.4
x=1.1
I'm glad to answer for you. I wish you a happy study!
4x=4.4
X = 1.1
What can be calculated by the square difference formula in the following formulas is ()
A. （-x+y）（x-y）B. （x-y）（y-x）C. （x+y）（x-2y）D. （x+y）（-x+y）
A. There is no item of opposite number, so this option is wrong; B. there is no item of opposite number, so this option is wrong; C, y and - 2Y, the absolute value of coefficient is not equal, so this option is wrong; D. it meets the requirements of square difference formula, so this option is correct; D
Using two different methods to solve the equation: 4 (X-10) + 6 (3-4x) = 7 (4x-3)
One is to solve the problem by opening brackets directly
One is to move the middle variable negative sign to the right and merge the similar terms to solve the problem
（1） (x-1)²(3x-2)+(2-3x) （2） a²+5a+6
Factorization
（1） (x-1)²(3x-2)+(2-3x)
=(3x-2)((x-1)^2-1)
=x(3x-2)(x-2)
（2） a²+5a+6
=(a-2)(a-3)
Solution equation: 2 / 3 [2 / 3 (1 / 4x-1) - 7 / 2] = x
2/3[3/2（1/4x-1）-7/2]=x
2/3[3/2（1/4x-1）-7/2]=x
[3/2（1/4x-1）-7/2]=3/2*x
3/2（1/4x-1）-7/2=3/2*x
3/8*x-3/2*x-3/2-7/2=0
-9/8*x=5
x=-40/9
2/3[2/3（1/4x-1）-7/2]=x
2/3*2/3(1/4x-1)-2/3*2/7=x
1/4x-1-3/7=x
3/4x=-10/3
x=-40/9