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過點A作AE⊥BC於E,AF⊥CD於F,∵兩條紙條寬度相同,∴AE=AF.∵AB‖CD,AD‖BC,∴四邊形ABCD是平行四邊形.∵S▱ABCD=BC•AE=CD•AF.又∵AE=AF.∴BC=CD,∴四邊形ABCD是菱形.故答案為:菱.
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