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設原正方形邊長為xcm 2(x+2)(x+1)-x*x=11 2x^2+6x+4-x^2-11=0 x^2+6x-7=0 (x+7)(x-1)=0 x=1,x=-7(舍去,邊長不能為負數) 原正方形面積=x*x=1*1=1平方釐米
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