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設其中一條直角邊長為xcm,則另一直角邊長為(14-x)cm,12×x(14-x)=24,解得x1=6,x2=8,當x1=6時,14-x=8;當x2=8時,14-x=6;答:兩條直角邊的長分別為6,8.
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